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Hoochie [10]
3 years ago
7

Help plss i need ittttt

Mathematics
1 answer:
MissTica3 years ago
3 0
I think it’s C.) add 5 to both sides
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Is the histogram uniform, symmetric, or skewed?
Sliva [168]
I'm pretty sure it is C
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3 years ago
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Kreem has 70 flowers.He gives away some flowers.now he has 2 flowers. how many flowers did Kreem give away.
vova2212 [387]

Answer:

68 flowers

Step-by-step explanation:

70-2=68, meaning Kreem has given away 68. 70-2=68, meaning Kreem has given away 68. 70-2=68, meaning Kreem has given away 68. 70-2=68, meaning Kreem has given away 68. 70-2=68, meaning Kreem has given away 68. 70-2=68, meaning Kreem has given away 68. 70-2=68, meaning Kreem has given away 68. 70-2=68, meaning Kreem has given away 68. 70-2=68, meaning Kreem has given away 68. 70-2=68, meaning Kreem has given away 68. 70-2=68, meaning Kreem has given away 68. 70-2=68, meaning Kreem has given away 68. 70-2=68, meaning Kreem has given away 68. 70-2=68, meaning Kreem has given away 68. 70-2=68, meaning Kreem has given away 68. 70-2=68, meaning Kreem has given away 68.

7 0
3 years ago
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27 + 18 + <br> = 59 plzzz help
lord [1]
After u add 18 u then add 15 and BOOM u have a answer which is 15
5 0
3 years ago
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Which choices are equivalent to the expression below? Check all that apply. √8 × √8
olya-2409 [2.1K]

Answer:

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4 0
2 years ago
Jacob has a bag of his favorite marbles. It has 3 red marbles, 4 blue, and 10 of his most favorite color, neon orange. What is t
drek231 [11]

Answer:

P(1\ and\ 2) = 0.3309

Step-by-step explanation:

Given

Red = 3

Blue = 4

Orange=10

Required

Probability of selecting 2 orange marbles

The total number of marbles is:

Total = Red + Blue + Orange

Total = 3 + 4 + 10

Total = 17

The probability that the first selection is orange is:

P(1) = \frac{10}{17}

Because it is a selection without replacement, the number of orange marbles and the total number of marbles would decrease by 1, respectively.

So, the probability that the selection is orange is:

P(2) = \frac{10-1}{17-1}

P(2) = \frac{9}{16}

The required probability is:

P(1\ and\ 2) = P(1) * P(2)

P(1\ and\ 2) = \frac{10}{17} * \frac{9}{16}

P(1\ and\ 2) = \frac{10*9}{17*16}

P(1\ and\ 2) = \frac{90}{272}

P(1\ and\ 2) = 0.3309

7 0
3 years ago
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