All categories

2 years ago

explain how to use estimation to help find the product of two decimals give a example of both estimated and actual answers

Mathematics

1 answer:

zmey [24]2 years ago

4 0

Answer:

To find a reasonable estimate using decimal numbers, round the decimal to the nearest whole number, so for example: 2.2 x 4.7 You can round 2.2 to 2 and 4.7 to 5 as they are the closest to the whole number.

2 x 5 = 10

Real answer:

10.34

You might be interested in

Help pls itS BEEN 2 HOURS LUV U <3

nataly862011 [7]

Step-by-step explanation:

Hey there!

The equation of a circle which passes through any point having centre (h,k) is;

$( {x - h)}^{2} + ( {y - k)}^{2} = {r}^{2}$

In first blank ( x-_ ) keep "-2". In second blank (y - _ ) keep "4" and in last blank ( _ ) keep "36".

Hope it helps..

7 0

2 years ago

Y= 5x - 9; domain = { 1,3,7 } what is the range values?

Maslowich

Answer:

Step-by-step explanation:

range = [-4,6,26]

Step-by-step explanation:

y = 5x - 9.....domain = [1,3,7]....the domain is ur x values, and I am assuming ur looking for the y values that go with the x ones

y = 5x - 9.....when ur domain (ur x) = 1

y = 5(1) - 9

y = 5 - 9

y = -4

y = 5x - 9...when ur domain (x) = 3

y = 5(3) - 9

y = 15 - 9

y = 6

y = 5x - 9...when ur domain(x) is 7

y = 5(7) - 9

y = 35 - 9

y = 26

so ur range (ur y valus) = [-4,6,26]

6 0

2 years ago

Leonard spent 1/4 of his money on a sandwich. He spent 2 times as much on a gift for his brother as on some comic books. He had

Oksana_A [137]

It's probably 2/6
Because comic books are 2 dollars and since he bought a sandwich it's 2/6 because the sandwich is 6 dallors

8 0

2 years ago

Find the zeros of y = x2 – 6x – 4 by completing the square.

katrin [286]

Answer:

The solutions to the quadratic equations are:

$x=\sqrt{13}+3,\:x=-\sqrt{13}+3$

Step-by-step explanation:

Given the function

$y\:=\:x^2\:-\:6x\:-\:4$

substitute y = 0 in the equation to determine the zeros

$0\:=\:x^2\:-\:6x\:-\:4$

Switch sides

$x^2-6x-4=0$

Add 4 to both sides

$x^2-6x-4+4=0+4$

Simplify

$x^2-6x=4$

Rewrite in the form (x+a)² = b

But, in order to rewrite in the form x²+2ax+a²

Solve for 'a'

2ax = -6x

a = -3

so add a² = (-3)² to both sides

$x^2-6x+\left(-3\right)^2=4+\left(-3\right)^2$

$x^2-6x+\left(-3\right)^2=13$

Apply perfect square formula: (a-b)² = a²-2ab+b²

$\left(x-3\right)^2=13$

$\mathrm{For\:}f^2\left(x\right)=a\mathrm{\:the\:solutions\:are\:}f\left(x\right)=\sqrt{a},\:-\sqrt{a}$

solve

$x-3=\sqrt{13}$

Add 3 to both sides

$x-3+3=\sqrt{13}+3$

Simplify

$x=\sqrt{13}+3$

now solving

$x-3=-\sqrt{13}$

Add 3 to both sides

$x-3+3=-\sqrt{13}+3$

Simplify

$x=-\sqrt{13}+3$

Thus, the solutions to the quadratic equations are:

$x=\sqrt{13}+3,\:x=-\sqrt{13}+3$

4 0

2 years ago

9:45 on Tuesday Questions

Kay [80]

Answer:

x = 3

Step-by-step explanation:

The angles are corresponding angles and they are equal by definition

120 = x + 123
x = 120 - 123
x = 3

3 0

2 years ago