Read the following statement:

. In the absence of the sodium-potassium pump, the extracellular solution becomes hypotonic relative to the inside of the cell.

andriy [413]

Answer:

sdfsdfsfsdf

Explanation:

sdfsfdsfsf

8 0

3 years ago

Compare a heterogeneous mixture and a homogeneous mixture

yarga [219]

In a heterogeneous mixture, you can clearly see the distinction between the different substances within the mixture. e.g. fruit salad, paella, nachos

in a homogeneous mixture, it is still made up of different substances, but there is no way of distinguishing between them just from appearances. they have the same uniform composition throughout. e.g. salt water; you know it is made of salt and water, but the salt is dissolved uniformly throughout that you cannot tell.

hope that helps :)

3 0

3 years ago

2

Law Incorporation [45]

Answer:

(a) W

(b) X

(c) Y

Explanation:

Let's consider the following table with melting and boiling points for 4 substances.

Substance Melting Point (°C) Boiling Point (°C)

W -7 60

X 660 2500

Y 180 1330

Z 115 445

Let's consider that:

Below the melting point, a substance is solid.
Between the melting and the boiling point, a substance is liquid.
Above the boiling point, a substance is gas.

(a) Which substance is a gas at 100°C?

At 100 °C, W is above the boiling point

(b) Which substance is a liquid for the largest range of temperature?

The largest difference between the melting point and the boiling point is that of X: 2500 - 660 = 1840.

(c) Which substance is liquid at 1000 °C and a gas at 2000°C?

Y is between the melting and the boiling point at 1000 °C and above the boiling point at 2000 °C.

3 0

3 years ago

An ion of a single pure element always has an oxidation number of ________.

aev [14]

Answer:

0

Explanation:

pure elements will always possess an oxidation number of 0, regardless of their charge.

3 0

3 years ago

Which aqueous solution would have the lowest vapor pressure at 25°c 1 M NaCl?

aleksley [76]

The question is incomplete, here is a complete question.

Which aqueous solution would have the lowest vapor pressure at 25°c.

A) 1 M NaCl

B) 1 M $K_3PO_4$

C) 1 M $C_{12}H_{10}O_{11}$

D) 1 M $MgCl_2$

E) 1 M $C_6H_{12}O_6$

Answer : The correct option is, (B) 1 M $K_3PO_4$

Explanation :

According to the relative lowering of vapor pressure, the vapor pressure of a component at a given temperature is equal to the mole fraction of that component of the solution multiplied by the vapor pressure of that component in the pure state.

1 M means that the 1 moles of solute present in 1 liter of solution.

Formula used :

$\frac{\Delta p}{p^o}=i\times X_B$

where,

$p^o$ = vapor pressure of the pure component (water)

$p_s$ = vapor pressure of the solution

$X_B$ = mole fraction of solute

i = Van't Hoff factor

As we know that the vapor pressure depends on the mole fraction of solute and the Van't Hoff factor.

So, the greater the number of particles of solute dissolved the lower the resultant vapor pressure.

(a) The dissociation of 1.0 M $NaCl$ will be,

$NaCl\rightarrow Na^++Cl^-$

So, Van't Hoff factor = Number of solute particles = $Na^++Cl^-$ = 1 + 1 = 2

(b) The dissociation of 1 M $K_3PO_4$ will be,

$K_3PO_4\rightarrow 3K^{+}+PO_4^{3-}$

So, Van't Hoff factor = Number of solute particles = $3K^{+}+PO_4^{3-}$ = 3 + 1 = 4

(c) The dissociation of 1 M $C_{12}H_{10}O_{11}$ is not possible because it is a non-electrolyte solute. So, the Van't Hoff factor will be, 1.

(d) The dissociation of 1.0 M $MgCl_2$ will be,

$MgCl_2\rightarrow Mg^{2+}+2Cl^{-}$

So, Van't Hoff factor = Number of solute particles = $Mg^{2+}+2Cl^{-}$ = 1 + 2 = 3

(e) The dissociation of 1 M $C_6H_{12}O_{6}$ is not possible because it is a non-electrolyte solute. So, the Van't Hoff factor will be, 1.

From this we conclude that, 1 M $K_3PO_4$ has the highest Van't Hoff factor which means that the solution will exhibit the lowest vapor pressure.

Hence, the correct option is, (B) 1 M $K_3PO_4$

8 0

3 years ago