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1 year ago

On the fahrenheit scale, at what temperature does water boil? a. 451°f b. 264°f c. 212°f d. 100°f

Chemistry

1 answer:

taurus [48]1 year ago

5 0

The temperature that water boils on the fahrenheit scale is c. 212°f.

<h3>What is Temperature conversation?</h3>

Temperature conversation is a way of converting a temperature from a unit to another using conversation scale.

Therefore, on fahrenheit scale water boils at 212°f which is equivalent to 100°C on the Celcius scale.

Learn more about Temperature conversation at;brainly.com/question/23419049

#SPJ4

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State two essential conditions for rusting of iron. List two methods of protecting iron from rusting?

gizmo_the_mogwai [7]

Conditions for rusting
• moisture
•oxygen

Prevention
•Painting
• Galvanisation
• Making Alloys
• greasing
Hope this helps you ;)(:

8 0

2 years ago

When cleaning up a local beach, students found many different particles that were in the water that affected the shoreline, like

ddd [48]

Your answer is C. Both gasoline and litter would need to be physically separated from the water, because neither bonds with the water.

8 0

3 years ago

Read 2 more answers

This compound, an eight-carbon alkane, serves as the 100 octane standard for gasoline. It has five methyl groups, one quaternary

Reika [66]

Answer:

2,2,4-Trimethyl-pentane

Explanation:

Structural characteristics of the compound is as follows:

Has five methyl group
Has one quaternary carbon
No. double bond
Gives four monochloro substitution products

Compound must have straight chain of 5 carbons.

Three methyl substituents are attached to 2 and 4 carbons.

Therefore, IUPAC name of the compound will be 2,2,4-Trimethyl-pentane.

5 0

2 years ago

How much of a sample remains after five half-lives have occurred?

timama [110]

Answer:

1/32 of the original sample

Explanation:

We have to use the formula

N/No = (1/2)^t/t1/2

N= amount of radioactive sample left after n number of half lives

No= original amount of radioactive sample present

t= time taken for the amount of radioactive samples to reduce to N

t1/2= half-life of the radioactive sample

We have been told that t= five half lives. This implies that t= 5(t1/2)

N/No = (1/2)^5(t1/2)/t1/2

Note that the ratio of radioactive samples left after time (t) is given by N/No. Hence;

N/No= (1/2)^5

N/No = 1/32

Hence the fraction left is 1/32 of the original sample.

3 0

3 years ago

Two unknown molecular compounds were being studied. A solution containing 5.00 g of compound A in 100. g of water froze at a low

Shtirlitz [24]

Answer:

Compound B.

Explanation:

The freezing point depression is a colligative property. It depends on the number of particles (moles) present in the solution.

$\Delta T_{\text{f}} = K_{\text{f}} b$

where b is the molal concentration

$b = \dfrac{\text{moles of solute}}{\text{kilograms of solvent}}\\\\n = \dfrac{\text{mass}}{\text{molar mass}} = \dfrac{m}{M}$

If m is constant (5 g), then

$n \propto \dfrac{1}{M}$

The compound with the greater molar mass has fewer moles and therefore fewer particles to depress the freezing point.

That must be Compound B, because Compound A has the lower freezing point.

7 0

2 years ago