Question

Help anyone can help me do the question 4,I will mark brainlest.​

Answer 1

Answer:

Hello,

Step-by-step explanation:

$A=(1,2)\\B=(0,-1)\\\overrightarrow{AB}=((0,-1)-(1,2)=(-1,-3)\ ||\overrightarrow{AB}||^2=1+9=10\\\overrightarrow{BC}=((3,-2)-(0,-1)=(3,-1)\ ||\overrightarrow{BC}||^2=9+1=10\\\\Triangle\ is\ isosceles.\\\\\overrightarrow{AB}.\overrightarrow{BC}=(-1,-3)*\left[\begin{array}{c}3\\-1\end{array}\right] =-3+3=0\\\\Triangle \ is\ right.$

Answer 2

Answer:

(Work below)

BRAINLIEST, PLEASE!

Step-by-step explanation:

A(1, 2) B(0, -1) C(3, -2)

The distance between A and B is:

3^2 + 1^2 = c^2

9 + 1 = c^2

c = 10^1/2

The distance between B and C is:

1^2 + 3^2 = c^2

1 + 9 = c^2

c = 10^1/2

The distance between C and A is:

4^2 + 2^2 = c^2

16 + 4 = c^2

c= 20^1/2

Since AB and BC are the same, but AC isn't, the triangle is isosceles.