Answer:
option A
Step-by-step explanation:
<span>(6y3 + 17y − 3) − (4y3 − 11y + 9)
</span>= 6y3 + 17y − 3 − 4y3 + 11y - 9
= 2y3 + 28y - 12
The correct answer is one solution
A function is positive if it lies above the x axis.
This function is positive before x = -4, i.e. over the interval 
It is negative elsewhere, i.e. over the interval 
So, the only correct option is the second one.
Answer:
B. Centers: the sea turtles have a greater median age than the koi
D. Spreads: the ages of the koi are more spread out
Step-by-step explanation:
The difference between the center and spread of the data distribution of koi and sea turtles as shown in the dot plots are as follows:
==>Median:
For Koi, the median value is the 14th value represented by the 14th dot on the plot, which is 30.
The median value for koi is between the 7th and the 8th value represented by dots on the plot. The average of both values will give us 55 as the median value for koi.
Therefore, the median age of sea turtle is greater than that of koi.
==>Spread:
Koi has a range of 45 (60-15), while sea turtles have a range of 20 (65-45). Invariably, mere looking at the dot plot, we can conclude that ages of the koi are more spread out.
