Answer:
97.3%
Step-by-step explanation:
Let the three bulbs be A, B and C respectively.
Let P(A) denote the probability that the first bulb will burn out
Let P(B) denote the probability that the second bulb will burn out
Let P(C) denote the probability that the third bulb will burn out
Now, we are told that Each one has a 30% probability of burning out within the month.
Thus;
P(A) = P(B) = P(C) = 30% = 0.3
Now, probability that at the end of the month at least one of the bulbs will be lit will be given as;
P(at least one bulb will be lit) = 1 - (P(A) × P(B) × P(C))
P(at least one bulb will be lit) = 1 - (0.3 × 0.3 × 0.3) = 0.973 = 97.3%
<span>f(5)= 2+5 = 7
</span><span>g(5)= 5^2+5 = 25 +5 = 30
</span><span>(f - g) (-5) = 7 - 30 = -23
answer is </span><span>D.-23</span>
688,747,536 ways in which the people can take the seats.
<h3>
</h3><h3>
How many ways are there for everyone to do this so that at the end of the move, each seat is taken by exactly one person?</h3>
There is a 2 by 10 rectangular greed of seats with people. so there are 2 rows of 10 seats.
When the whistle blows, each person needs to change to an orthogonally adjacent seat.
(This means that the person can go to the seat in front, or the seats in the sides).
This means that, unless for the 4 ends that will have only two options, all the other people (the remaining 16) have 3 options to choose where to sit.
Now, if we take the options that each seat has, and we take the product, we will get:
P = (2)^4*(3)^16 = 688,747,536 ways in which the people can take the seats.
If you want to learn more about combinations:
brainly.com/question/11732255
#SPJ!
13. if edward wins 6 of his remaining games...that would make a total of 12 wins (since he already won 6 earlier)
3/4 as many winsa as edward....3/4(12) = 36/4 = 9...so he would have to win 9 to have 3/4's as much as edward...and howard has already won 4...so he needs (9 - 4) = 5....he needs 5 wins
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14. Robert has already won 2, and he has lost 8...so he would have to win at least 7 of his games to have more wins then losses
