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3 years ago

How to tell if an equation is linear or not

1 answer:

8 0

A linear<span> function is in the form y = mx + b or f(x) = mx + b, where m is the slope or rate of change and b is the y-intercept or where the graph of the line crosses the y axis. You will notice that this function is degree 1 meaning that the x variable has an exponent of 1.</span>

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Which relation does not represent a function? Question 2 options: A) { (3, 0) (0, 3) } B) { (6, -2) (5, -2) } C) { (3, 4)

Katyanochek1 [597]

C because the x's repeat with the 3 and 3. If the x's repeat it is not a function.

Hope that helps.

5 0

3 years ago

Read 2 more answers

The area of a rectangle is represented by x^2-5c-14. What are the dimensions?

jekas [21]

The dimensions are factors of the expression
... you multiply them together to get the area

the factors are ... (x - 7) & (x + 2)

5 0

3 years ago

The line L is a tangent to the curve with equation y= 4x^2 +1 . The line L cuts the y axis at (0,8) and has a positive gradient.

sergeinik [125]

A generic point on the graph of the curve has coordinates

$(x, 4x^2+1)$

The derivative gives us the slope of the tangent line at a given point:

$f(x) = 4x^2+1 \implies f'(x) = 8x$

Let k be a generic x-coordinate. The tangent line to the curve at this point will pass through $(k, 4k^2+1)$ and have slope $8k$

So, we can write its equation using the point-slope formula: a line with slope m passing through $(x_0, y_0)$ has equation

$y-y_0 = m(x-x_0)$

In this case, $(x_0, y_0)=(k, 4k^2+1)$ and $m=8k$ , so the equation becomes

$y-4k^2-1 = 8k(x-k)$

We can rewrite the equation as follows:

$y-4k^2-1 = 8k(x-k) \iff y = 8kx - 8k^2+4k^2+1 \iff y = 8kx-4k^2+1$

We know that this function must give 0 when evaluated at x=0:

$f(x) = 8kx-4k^2+1 \implies f(0) = -4k^2+1 = 8 \iff -4k^2 = 7 \iff k^2 = -\dfrac{7}{4}$

This equation has no real solution, so the problem looks impossible.

5 0

3 years ago

35 X 6.7<br> What is this answer

Rama09 [41]

Answer:

234.5

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

To put up several tents for a camping trip, you need several pieces of rope each 6 2/3 feet long. If you have a rope that is 43

Otrada [13]

$\bf 43\div 6\frac{2}{3}\implies \cfrac{46}{6\frac{2}{3}}\implies \cfrac{\frac{46}{1}}{\frac{6\cdot 3+2}{3}}\implies \cfrac{\frac{46}{1}}{\frac{20}{3}} \implies \cfrac{46}{1}\cdot \cfrac{3}{20}\implies \cfrac{69}{10}
\\\\\\
\boxed{6\frac{9}{10}}\qquad \qquad 
\cfrac{6\cdot 10+9}{10}\implies \cfrac{69}{10}$

3 0

3 years ago