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3 years ago

I need help with this question

Mathematics

1 answer:

Semmy [17]3 years ago

7 0

40 it's the same angle as angle A rotation doesn't change anything

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The gasoline gauge on a van initially read one fourth14 full. when 1010 gallons were added to the tank, the gauge read two thir

antoniya [11.8K]

First, have common denominators.
1/4 = 3/12
2/3 = 8/12
8/12 - 3/12 = 5/12 or 1,010 gallon
1,010/5 gallon = 1/12 full
202 gallons = 1/12 full
7/12 needed until full ⇒ 7*202 = 1,414 gallons

7 0

3 years ago

Is 4(x + 2y) + 4x equal to 8(x + y)?<br> Yes or no

Sever21 [200]

Answer:

Yes

4x + 8y + 4x = 8x + 8y

8x + 8y = 8x + 8y

5 0

3 years ago

Read 2 more answers

A photo is 8 cm long and 6 cm wide. It is enlarged to make a print that is 18 cm wide.

dezoksy [38]

Answer:

24 cm

Step-by-step explanation:

The photo was 6 cm wide, and was made into 18 cm wide. Divide 18 with 6:

18/6 = 3

To solve for the length enlargement, multiply 3 with the length, or 8 cm:

8 x 3 = 24

24 cm is the length of the enlargement.

3 0

3 years ago

The no. Of adel beads to that of claire's beads was the ratio 7 :4 .When adel gave 68 beads to claire the ratio become 25 :41 .

Novosadov [1.4K]

Answer:

37 beads

Step-by-step explanation:

Given that:

Adel : Claire = 7 : 4

Let Adel be = A; &

Let Claire be = C

A: C = 7 : 4

$\dfrac{A}{C} =\dfrac{7}{4}$

7C = 4A

$C = \dfrac{4A}{7}$ --- (1)

When Adel gave 68 beads to claire, we have:

C + 68 = 25:41

$\dfrac{A}{C+68}= \dfrac{25}{41}$

25(C + 68) = 41A

C + 68 = $\dfrac{41}{25}A$

$C = \dfrac{41}{25}A - 68$ --- (2)

Equating (1) and (2) together;

$\dfrac{4 * A}{7} = \dfrac{41 *A}{25} - 68$

$\dfrac{4 * A}{7}-\dfrac{41 *A}{25} = - 68$

$\dfrac{100A - 287 A}{175} =- 68$

$\dfrac{-187A}{175} = -68$

- 187 A = 175 × (-68)

-187 A = - 11900

A = - 11900/ -187

A ≅ 64

From; $C = \dfrac{4A}{7}$

$C = \dfrac{4*64}{7}$

C = 36.57

C ≅ 37 beads

4 0

3 years ago

2.072539 rounded to the nearest hundredth

zalisa [80]

Answer:

2.07

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers