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3 years ago

For one minute Every 5th caller will win a Music player and every 7th caller

Mathematics

1 answer:

Assoli18 [71]3 years ago

8 0

to do this you have to find the lcm of 5 & 7 which is 35

-hope this helps

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Tom earns $24 a week mowing lawns. He spends 1/8 of his earnings on lunch and 3/4 of his earnings on music. He saves the rest.

gayaneshka [121]

Answer:

Step-by-step explanation:

24-3-18=3

3 0

3 years ago

Solve 10x^5y^12/-5x^-2y^6

Stells [14]

(10x5y12−5x−2)(y6)=−2x5y18x2=−2x3y18

5 0

3 years ago

5k-7=-7 solve the equation to what is k

LenKa [72]

So 5k-7=-7
You need to do the opposite of addition,which is subtraction so...
5k-7=-7
+7
__
K=0
and to double check it,replace the (or variable) with our answer (0)...
so
5×0-7=-7
solve the problem...and
-7=-7√

5 0

4 years ago

Read 2 more answers

Divide £700 in the ratio 6:4 (2 marks)

SpyIntel [72]

Answer:

One num = 6x = 6 x 70 = 420

Second= 4x = 4 x 70 = 280

Step-by-step explanation:

6x + 4x = 700

10x = 700

x = 700/10 = 70

One num = 6x = 6 x 70 = 420

Second= 4x = 4 x 70 = 280

I hope im right!

7 0

3 years ago

What is the definite integral of log (tan x) with range from 90 to 0

nasty-shy [4]

Substituting x with π/2 - x gives the equivalent integral,

$\displaystyle\int_0^{\frac\pi2}\log(\tan(x))\,\mathrm dx=-\int_{\frac\pi2}^0\log(\cot(x))(-\mathrm dx)=\int_0^{\frac\pi2}\log(\cot(x))\,\mathrm dx$

So if we let J denote the value of the integral, we have

$J=\displaystyle\int_0^{\frac\pi2}\log(\tan (x))\,\mathrm dx$

$J=\displaystyle\int_0^{\frac\pi2}\log(\cot (x))\,\mathrm dx$

$\implies 2J=\displaystyle\int_0^{\frac\pi2}\left(\log(\tan (x))+\log(\cot (x))\right)\,\mathrm dx$

Condensing the logarithms, we have

log(tan(x)) + log(cot(x)) = log(tan(x) cot(x)) = log(1) = 0

since cot(x) = 1/tan(x), which means

$2J=\displaystyle\int_0^{\frac\pi2}0\,\mathrm dx=0$

and so the original integral has a value of J = 0.

3 0

3 years ago