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3 years ago

HELPPP pleasssse and thankssssss

Mathematics

1 answer:

Fynjy0 [20]3 years ago

4 0

Answer:

VW=4

Step-by-step explanation:

UW=VW+UV

5x-5=(x)+(3x-1)

5x-5=4x-1

5x-4x=-1+5

x=4

VW=x= 4

I hope I helped you^_^

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If the scale factor from shape A to B is 5. What is the scale factor from shape B to A?

OLga [1]

Answer:

1/5

Step-by-step explanation:

You need the opposite of 5/1 which would be 1/5

6 0

2 years ago

1. Graph the line y=2x+5 on the graph.

alisha [4.7K]

Answer:

See below

Step-by-step explanation:

We can simply use a graphing calculator to carry it out.

See the attached file for more explanation!

Another way is that we can take the values of x as 1,2 and 3 and so on and put it in the equation to get the value of y. We have some coordinates now so we'll plot them in the graph to get the line of y = 2x+5.

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3 years ago

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kondor19780726 [428]

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4 0

4 years ago

What is the answer to d- 48.60 = 80.00

Gwar [14]

Answer:

31.4

Step-by-step explanation:

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8 0

3 years ago

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A model rocket is launched with an initial upward velocity of 126 ft/s. The rocket's height h (in feet) after 1 seconds is given

Vlad [161]

Step-by-step explanation:

f(t) = -16t² + 126t

for what values of t did this function deliver 50 ft of height ?

50 = -16t² + 126t

-16t² + 126t - 50 = 0

the general solution to such a squared equation is

x = (-b ± sqrt(b² - 4ac))/(2a)

in our case

x = t

a = -16

b = 126

c = -50

t = (-126 ± sqrt(126² - 4×-16×-50))/(2×-16) =

= (-126 ± sqrt(15876 - 3200))/-32 =

= (-126 ± sqrt(12676))/-32 =

= (-126 ± 112.5877436...)/-32

t1 = (-126 + 112.5877436...)/-32 = -13.41225644.../-32 =

= 0.419133014... ≈ 0.42 seconds

t2 = (-126 - 112.5877436...)/-32 = -238.5877436.../-32 =

= 7.455866986... ≈ 7.46 seconds

so, this means, right after launch the ticket reaches 50ft (from below) after 0.42 seconds, and then, when it falls back down, it will reach 50ft again (this time from above) after 7.46 seconds of flight time.

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2 years ago