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dexar [7]
3 years ago
10

What is the distributive property of 60 - 50?

Mathematics
2 answers:
MAVERICK [17]3 years ago
5 0
Seriously? 60 minus 50 equals 10.
lions [1.4K]3 years ago
5 0
60 - 50 = 10
Simple.
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(6t^4-t+1) - (6t^3-4t)
goldenfox [79]

Answer:

= 6 {t}^{4}   - 6 {t}^{3}  + 3t + 1

Step-by-step explanation:

6 {t}^{4}  - t + 1 - 6 {t}^{3}  + 4t \\  = 6 {t}^{4}   - 6 {t}^{3}  + 3t + 1

5 0
3 years ago
Can you please help me?!
Fudgin [204]

Answer:

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Step-by-step explanation:

4 0
3 years ago
I need help with this problem. ​
MariettaO [177]

Answer:

the numbers next to a variable is a coefficient, for instance in 2x 2 would be the coefficient.

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3 years ago
Find the 14th term of the sequence using the explicit rule:
Vesna [10]
Plug n = 14 into the formula

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5 0
3 years ago
A small business owner estimates his mean daily profit as $970 with a standard deviation of $129. His shop is open 102 days a ye
Katena32 [7]

Answer:

The probability that the shopkeeper's annual profit will not exceed $100,000 is 0.2090.

Step-by-step explanation:

According to the Central Limit Theorem if we have a population with mean <em>μ</em> and standard deviation <em>σ</em> and we select appropriately huge random samples (<em>n</em> ≥ 30) from the population with replacement, then the distribution of the sum of values of <em>X</em>, i.e ∑<em>X</em>, will be approximately normally distributed.  

Then, the mean of the distribution of the sum of values of X is given by,  

 \mu_{x}=n\mu

And the standard deviation of the distribution of the sum of values of X is given by,  

 \sigma_{x}=\sqrt{n}\sigma

The information provided is:

<em>μ</em> = $970

<em>σ</em> = $129

<em>n</em> = 102

Since the sample size is quite large, i.e. <em>n</em> = 102 > 30, the Central Limit Theorem can be used to approximate the distribution of the shopkeeper's annual profit.

Then,

\sum X\sim N(\mu_{x}=98940,\ \sigma_{x}=1302.84)

Compute the probability that the shopkeeper's annual profit will not exceed $100,000 as follows:

P (\sum X \leq  100,000) =P(\frac{\sum X-\mu_{x}}{\sigma_{x}}

                              =P(Z

*Use a <em>z</em>-table for the probability.

Thus, the probability that the shopkeeper's annual profit will not exceed $100,000 is 0.2090.

6 0
3 years ago
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