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3 years ago

11

if x is th didit at tense place and y is the digit at ones place,the two digit number formed by these digits is.................

......

1 answer:

svp [43]3 years ago

8 0

Answer:

<em>I </em><em>think</em><em> the</em><em> two</em><em> </em><em>digit </em><em>number</em><em> </em><em>formed </em><em>would </em><em>be </em>

<em>xy</em>

<em>seeing</em><em> </em><em>that </em><em>x </em><em>is </em><em>on </em><em>the </em><em>tens </em><em>place </em><em>which </em><em>is </em><em>the </em><em>second</em><em> </em><em>last </em><em>place </em><em>and </em><em>y </em><em>is </em><em>on </em><em>the </em><em>ones </em><em>place </em><em>meaning</em><em> </em><em>it </em><em>has </em><em>to </em><em>be </em><em>the </em><em>last </em><em>value.</em>

<em>I</em><em> hope</em><em> this</em><em> helps</em>

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3 years ago

E + f =48<br> e=3f<br> Plz help - thanks

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Answer:

$given \: \\ \\ e = 3f \\ e + f = 48 \\ \\ 3f + f = 48 \\ 4f = 48 \\ f = \frac{48}{4} \\ f = 12 \\ so. \\ e = 3 \times 12 = 36$

<h2><em>plzz mark it as a brilliant ans</em></h2>

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