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Otrada [13]
3 years ago
14

Ana bikes for 5.5 hours. She covers a distance of 57.75 mi. Assuming she bikes at a constant speed, how fast was Ana biking?

Mathematics
2 answers:
Anastaziya [24]3 years ago
5 0

Answer:

D. 10.5 mi/h

Step-by-step explanation:

I took the test online in K12 and when I reviewed it said that 10.5 is the correct answer.

Doss [256]3 years ago
3 0
The answer is D. because if you do 57.75 divided by 5.5 you get 10.5 mi/h



hope this helps :)
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A jar contains 16 quarters, 6 dimes ,7 nickels and 11 pennies, if one coin is selected at random, what is the probability it is
maksim [4K]

Answer:

11/20

Step-by-step explanation:

5 cents is worth $0.05.

A quarter is worth $0.25.

A dime is worth $0.10

A nickel is worth $0.05

A penny is worth $0.01

In total there are 40 coins in the jar.

The coins that are worth more than $0.05 dollars are the dimes and quarters, so there are 22 coins worth more than $0.05.

Therefore, the probability of of picking a coin worth more than 5 cents is:

22 / 40 = 11/20

5 0
3 years ago
What are the solutions to the equation <br><img src="https://tex.z-dn.net/?f=%20%7Cx%20-%208%7C%20%20%2B%202%20%3D%2020" id="Tex
nexus9112 [7]

Answer:

Solutions are -10 and 26

Step-by-step explanation:

( - the abolute sign I'm using

( x - 8 ) + 2 = 20

( x - 8 ) = 18

x - 8 = 18 (postive case)

x - 8 + 8 = 18 + 8

x = 26

( x - 8 ) = 18

x - 8 = -18 (negative case)

x - 8 + 8 = -18 + 8

x = -10

8 0
3 years ago
John, Joe, and James go fishing. At the end of the day, John comes to collect his third of the fish. However, there is one too m
Dmitry [639]

Answer:

The minimum possible initial amount of fish:52

Step-by-step explanation:

Let's start by saying that

x = is the initial number of fishes

John:

When John arrives:

  • he throws away one fish from the bunch

x-1

  • divides the remaining fish into three.

\dfrac{x-1}{3} + \dfrac{x-1}{3} + \dfrac{x-1}{3}

  • takes a third for himself.

\dfrac{x-1}{3} + \dfrac{x-1}{3}

the remaining fish are expressed by the above expression. Let's call it John

\text{John}=\dfrac{x-1}{3} + \dfrac{x-1}{3}

and simplify it!

\text{John}=\dfrac{2x}{3} - \dfrac{2}{3}

When Joe arrives:

  • he throws away one fish from the remaining bunch

\text{John} -1

  • divides the remaining fish into three

\dfrac{\text{John} -1}{3} + \dfrac{\text{John} -1}{3} + \dfrac{\text{John} -1}{3}

  • takes a third for himself.

\dfrac{\text{John} -1}{3}+ \dfrac{\text{John} -1}{3}

the remaining fish are expressed by the above expression. Let's call it Joe

\text{Joe}=\dfrac{\text{John} -1}{3}+ \dfrac{\text{John} -1}{3}

and simiplify it

\text{Joe}=\dfrac{2}{3}(\text{John}-1)

since we've already expressed John in terms of x, we express the above expression in terms of x as well.

\text{Joe}=\dfrac{2}{3}\left(\dfrac{2x}{3} - \dfrac{2}{3}-1\right)

\text{Joe}=\dfrac{4x}{9} - \dfrac{10}{9}

When James arrives:

We're gonna do this one quickly, since its the same process all over again

\text{James}=\dfrac{\text{Joe} -1}{3}+ \dfrac{\text{Joe} -1}{3}

\text{James}=\dfrac{2}{3}\left(\dfrac{4x}{9} - \dfrac{10}{9}-1\right)

\text{James}=\dfrac{8x}{27} - \dfrac{38}{27}

This is the last remaining pile of fish.

We know that no fish was divided, so the remaining number cannot be a decimal number. <u>We also know that this last pile was a multiple of 3 before a third was taken away by James</u>.

Whatever the last remaining pile was (let's say n), a third is taken away by James. the remaining bunch would be \frac{n}{3}+\frac{n}{3}

hence we've expressed the last pile in terms of n as well.  Since the above 'James' equation and this 'n' equation represent the same thing, we can equate them:

\dfrac{n}{3}+\dfrac{n}{3}=\dfrac{8x}{27} - \dfrac{38}{27}

\dfrac{2n}{3}=\dfrac{8x}{27} - \dfrac{38}{27}

L.H.S must be a Whole Number value and this can be found through trial and error. (Just check at which value of n does 2n/3 give a non-decimal value) (We've also established from before that n is a multiple a of 3, so only use values that are in the table of 3, e.g 3,6,9,12,..

at n = 21, we'll see that 2n/3 is a whole number = 14. (and since this is the value of n to give a whole number answer of 2n/3 we can safely say this is the least possible amount remaining in the pile)

14=\dfrac{8x}{27} - \dfrac{38}{27}

by solving this equation we'll have the value of x, which as we established at the start is the number of initial amount of fish!

14=\dfrac{8x}{27} - \dfrac{38}{27}

x=52

This is minimum possible amount of fish before John threw out the first fish

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2 years ago
What is the slope of a line that passes through the points (-8, 14) and (4,-4)?
Simora [160]

Answer:

the answer is -3/2

Step-by-step explanation:

Trust me its correct

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2 years ago
Write an explicit (function) rule for the sequence 10, 12, 14, 16,...
Alexeev081 [22]
Option d is the correct answer
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3 years ago
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