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Wewaii [24]
2 years ago
6

Write an equation for the line that passes through (- 3, 5) and is parallel to y = - 6x + 1.

Mathematics
1 answer:
soldier1979 [14.2K]2 years ago
3 0

Answer:

y-5 = -6(x+3) OR y = -6x-13

Step-by-step explanation:

Let's use slope-intercept form to solve this problem.

Slope intercept form is the following:

y-y1 = m(x-x1)

x1 and y1 are given by the point in the problem.

x1 = -3, y1 = 5.

m is given by the equation in the problem. Lines that are parallel have the same slope. Thus,

m = -6.

If we plug these values into the equation for slope intercept form, we get the following:

y-5 = -6(x-(-3)) which becomes y-5 = -6(x+3)

This is an acceptable answer to the problem. However, point-slope form is also a way it can be written.

y-5 = -6x-18

y = -6x-13

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Please help me!<br> Hint: the number is negative
wel

Answer:

-36 goes into the box

Step-by-step explanation:

Let the number be x,  then


(m^x)^{\frac{1}{3}}=m^{-12}


We now use the following property of exponents to simplify the left hand side of the equation.

(a^m)^n=a^{mn}

This implies that;

m^{x\times \frac{1}{3}}=m^{-12}


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6 0
3 years ago
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marin [14]

Answer:

Step-by-step explanation:

18 7/8 - 14 7/9

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3 years ago
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kykrilka [37]

Answer:

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Step-by-step explanation:

Using the rule of radicals

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Given

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