Answer:
4, -2
Step-by-step explanation:
I used the calculator
Wat grade are uu in?.....
The answer is A (54pi square cm)
Answer:
V = πr²h
S=2πrh
h= 2/3 millimeters
new height= 8/3 millimeters
S= 8π millimeters square
New surface area = 32π millimeters square
Step-by-step explanation:
The volume of the cylinder is given by V = πr²h where r is the radius and h is the height.
The surface area of the cylinder is given by S= 2πrh + 2πr²
Where πr² gives the area of the base and 2πr² gives the area of the top and bottom surfaces. The surface area S of a cylinder, not including the top and bottom of the cylinder, is therefore S=2πrh.
V = πr²h
96π= π (6*6) (h+2)
96 = 36 (h+2)
96/36= h+2
h= 96/36-2
h= 96-72/36
h= 24/36
h= 4/6
h= 2/3 millimeters
New height
h + 2= 2/3 + 2
= 2+6/3= 8/3 millimeters
Now S =2πrh
S = 2π(6) (2/3)
S= 8π millimeters square
New Surface area
S = 2π(6) (8/3)
S= 32π millimeters square
Answer:
256/3 = 85 1/3 square inches
Step-by-step explanation:
The dimensions of the first inscribed triangle are 1/2 those of the original, so its area is (1/2)² = 1/4 of the original. The area of the original is ...
A = (1/2)bh = (1/2)(16/√2)(16/√2) = 64 . . . . square inches
The sum of an infinite series with first term 64 and common ratio 1/4 is ...
S = a1/(1 -r) . . . . . . for first term a1 and common ratio r
= 64/(1 -1/4) = 64(4/3) = 256/3 . . . . square inches
The sum of the areas of the triangles is 256/3 = 85 1/3 square inches.
