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Vaselesa [24]
3 years ago
14

18 cards are numbered from 11 to 29 if one card is chosen at random, what is the probability that if contains the digit ​

Mathematics
1 answer:
Mumz [18]3 years ago
5 0
What digit? 2?
If it’s two:

“There are 29–10 = 19 cards in total. There are 11 cards that has at least one 2 on it (12, 20–29). The probability of choosing a card with a 2 on it is 11/19.”
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Find the length of BC. <br> A.) 14<br> B.) 9<br> C.) 2<br> D.) 3
Vera_Pavlovna [14]

Answer:

A) 14

Step-by-step explanation:

BC is congruent to DC in saying this you can plug the equations to each other and solve for y and then put its back into the equation for BC to get the length.

3y+5=5y-1

subtract 3y from both sides --> 5=2y-1

add 1 to both sides --> 6=2y

now get y alone, divide by 2 by both side --> y=3

plug y in back to 5y-1 --> 5x3-1

15-1

BC = 14

7 0
3 years ago
Write the standard form of the equation of the line that passes through point at (4,2) and is parallel to whose equation is y=2x
solong [7]
Since the equation is parallel to y=2x-4 that means they have the same slope. Now that you have the slope and fortunately a point, you can solve this by using point slope formula
y - y1 = m(x - x1)
Which is what I did on the attached picture and just rearrange it after solving to Ax+By=C/2x-y=6

6 0
4 years ago
Containers A (6cm, 5cm, 4cm), B (5cm, 4cm, 3 cm) and C (3cm, 3cm, 2 cm) are three rectangular containers. At first, container A
motikmotik

Answer:

Step-by-step explanation:

8 0
3 years ago
Solve for x. Show your work. -12x &lt; -12
Eva8 [605]

Step-by-step explanation:

-12x < -12

-12x/-12= x

-12/-12= 1

x < 1

3 0
3 years ago
Read 2 more answers
A cylindrical tank holds 352 cu. ft. of water. The height of the tank is 7 ft. Find the
Rzqust [24]

Answer:

0.3334 ft

Step-by-step explanation:

Measure the height and radius of the tank. The radius is the distance from the center of the tank to its outer edge. Another way to find the radius is to divide the diameter, or width, by two. Square the radius by multiplying the radius times itself and then multiply it by 3.1416, which is the constant pi.

  1. Given height and volume: r = √(V / (π * h)),
  2. Given height and lateral area: r = A_l / (2 * π * h),
  3. Given height and total area: r = (√(h² + 2 * A / π) - h) / 2,
  4. Given height and diagonal: r = √(h² + d²) / 2,
  5. Given height and surface-area-to-volume ratio: r = 2 * h / (h * SA:V - 2),
  6. Given volume and lateral area: r = 2 * V / A_l,
  7. Given base area: r = √(A_b / (2 * π)),
  8. Given lateral area and total area: r = √((A - A_l) / (2 * π)).
4 0
3 years ago
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