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2 years ago

Graph a line with a slope of -2/5 that contains the point (-3,5)

Mathematics

2 answers:

riadik2000 [5.3K]2 years ago

5 0

Answer:

Thx for the points

Step-by-step explanation:

lesya [120]2 years ago

3 0

Answer:

Step-by-step explanation:

step 1: identify the x1, y1 and slope

x1 = -3

y1 = 5

m(slope) = -2/5

Step 2: plug the points that you identified into the point slope form equation.

Point slope form: y - y1 = m(x-x1) ---> this is one of the general equation that will help you find the equation for a function when given a point and slope.

y - 5 = -2/5(x -(-3))

y - 5 = -2/5(x + 3)

y - 5 = (-2/5)x -6/5

y = (-2/5)x + 19/5

Step 3:

Plug in at least 2 points and graph them. You should get a graph similar to the one in the screenshot.

I hope this helps!

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3 years ago

In 2003 a town’s population was 1431. By 2007 the population had grown to 2134. Assume the population is changing linearly.How m

sergiy2304 [10]

We will have the following:

First, we will have that the population change by:

$\Delta P=2134-1431\Rightarrow\Delta P=703$

So, the population changed by 703 people.

It took the follwoing number of years to change from 1431 to 2134:

$\Delta y=2007-2003\Rightarrow\Delta y=4$

So, it took 4 years to changes from 1431 to 2134.

$m=\frac{2134-1431}{2007-2003}\Rightarrow m=175.75$

The average population growth per year is of 175.75 people per year.

The population in 2000 would have been:

$P_{2000}=\frac{2000\cdot1431}{2003}\Rightarrow P_{2000}=1428.856715\ldots$

$\Rightarrow P_{2000}\approx1429$

So, the population in 2000 would have been approximately 1429 people.

We will have that the equation for the population would be:

$P=(\frac{2134-1431}{2007-2003})t+1429\Rightarrow P=\frac{703}{4}t+1429$

So, the equation would be:

$P=175.75t+1429$

Now, we predict the number of people of the town in 2014:

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3 0

1 year ago

What is the probability that more than twelve loads occur during a 4-year period? (Round your answer to three decimal places.)

Nataly_w [17]

Answer:

Given that an article suggests

that a Poisson process can be used to represent the occurrence of

structural loads over time. Suppose the mean time between occurrences of

loads is 0.4 year. a). How many loads can be expected to occur during a 4-year period? b). What is the probability that more than 11 loads occur during a

4-year period? c). How long must a time period be so that the probability of no loads

occurring during that period is at most 0.3?Part A:The number of loads that can be expected to occur during a 4-year period is given by:Part B:The expected value of the number of loads to occur during the 4-year period is 10 loads.This means that the mean is 10.The probability of a poisson distribution is given by where: k = 0, 1, 2, . . ., 11 and λ = 10.The probability that more than 11 loads occur during a

4-year period is given by:1 - [P(k = 0) + P(k = 1) + P(k = 2) + . . . + P(k = 11)]= 1 - [0.000045 + 0.000454 + 0.002270 + 0.007567 + 0.018917 + 0.037833 + 0.063055 + 0.090079 + 0.112599 + 0.125110+ 0.125110 + 0.113736]= 1 - 0.571665 = 0.428335 Therefore, the probability that more than eleven loads occur during a 4-year period is 0.4283Part C:The time period that must be so that the probability of no loads occurring during that period is at most 0.3 is obtained from the equation:Therefore, the time period that must be so that the probability of no loads

occurring during that period is at most 0.3 is given by: 3.3 years

Step-by-step explanation:

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