Ask question

Ask question

All categories

3 years ago

6

Out of a group of 130, 80 people like basketball, 70 like soccer, 50 like both, what is the probablity if you choose randomly th

at you get someone that likes both?

1 answer:

nasty-shy [4]3 years ago

3 0

50 like both out of 130 total
Divide: 50/130 = 5/13

The answer as a fraction is exactly 5/13
The approximate answer is 0.3846

You might be interested in

The function for the cost of materials to make a muffin is f(x) = Three fourths x + 3, where x is the number of muffins. The fun

velikii [3]

(3x+4)(x+3)
(3x20)(20+3)
(60)(23)
1380

8 0

2 years ago

PLZZZZZZZ HELPP Which ordered pair is the solution to the system of equations? {y=2x−15} {4x+3y=−5} (5, −5) (4, −7) (0, 6) (7

Sophie [7]

solution is (4, - 7 )

given the equations

y = 2x - 15 → (1)

4x + 3y = - 5 → (2)

substitute y = 2x - 15 into (2)

4x + 3(2x - 15) = - 5

4x + 6x - 45 = - 5

10x - 45 = - 5 ( add 45 to both sides )

10x = 40 ( divide both sides by 10 )

x = 4

substitute x = 4 into (1) for corresponding value of y

y = (2 × 4 ) - 15 = 8 - 15 = - 7

solution is (4, - 7 )

8 0

2 years ago

5. The combined perimeter of a circle and a square is 16. Find the dimensions of the circle and square

charle [14.2K]

aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaq

8 0

2 years ago

Pleeeaasseeee help me and my friend have been working on this for a bit

RideAnS [48]

Let me try and solve

8 0

2 years ago

Read 2 more answers

Plz show work and solve quick please need help!!!!!

Simora [160]

Surface area is just the area of all these 4 triangles plus the rectangle.

First we can find the area of the rectangle.

$\sf A=lw$

Half of the length is 28 cm, so the full length must be 28 * 2 = 56 cm.

$\sf A=(56)(27)$

$\sf A=1512cm^2$

The base for the left and right triangles are 27. The heights would be the net length minus half the length of the rectangle:

$\sf 82.8-28=54.8\? cm$

Calculate the area:

$\sf A=\dfrac{1}{2}bh$

$\sf A=\dfrac{1}{2}(27)(54.8)$

$\sf A=739.8\?cm^2$

We have two of these triangles.

$\sf 739.8\times 2=1479.6\? cm^2$

Now do the other two pair of triangles. The bases for them are 28 + 28 = 56 cm. The heights would be the net width minus the width of the rectangle:

$\sf 81.2-27=54.2\?cm$

Now find the area:

$\sf A=\dfrac{1}{2}bh$

$\sf A=\dfrac{1}{2}(56)(54.2)$

$\sf A=1517.6\? cm^2$

We have two of these triangles.

$\sf 1517.6\times 2=3035.2\?cm^2$

Add all the areas together:

$\sf 1512+1479.6+3035.2=\boxed{\sf 6026.80\? cm^2}$

7 0

3 years ago