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arsen [322]
3 years ago
7

I need a Hashtag relating to the cell wall

Biology
1 answer:
rosijanka [135]3 years ago
7 0
#onlyexistsinplantscell
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You set up an experiment with yeast grown on lots of food (glucose) vs. very little glucose. Would you expect to see differences
k0ka [10]

Answer:

yes

Explanation:

The RNA, is composed by the carbohydrate called ribose, that is not glucose but it is made based of the glucose.

The pentose phosphate path, is a metabolic path in which is closely related with glucolisis, the metabolic path in which glucose is turned into energy in human body.

If there is a living thing in which the environment is poor in glucose, it can produce some RNA, but not the necessary to produce the proteins that the cell need.

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3 years ago
A generator converts mechanical energy into _____________________ energy.
FinnZ [79.3K]
An Engine-generator, commonly called a generator, converts chemical energy in gasoline into rotary mechanical energy, which is converted into B) electrical energy
8 0
3 years ago
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What structure covers organs of mollusks?
Fed [463]
I believe that would be the mantle. Hope this helped!
7 0
4 years ago
Infer why there might be so many more of one kind of flatworm than any other kind :)
xz_007 [3.2K]

Answer: There might be more of one kind of flatworm than any other because they adapt more to their enviorment than any worm. OR its because they have more access to resources

on: (any answer is correct because you are making a inference)

8 0
3 years ago
the frequency of a wave in a stretched string depends on the length L, tension T and linear density m with dimension ML-1 . dedu
spin [16.1K]

Answer:

f = \frac{1 }{L}\sqrt{\frac{T}{m} }

Explanation:

Let the frequency ,

f = L^{x}T^{y}m^{z}

Now the unit of frequency is hertz = s⁻¹ = T⁻¹ where T is time, tension T = kgm/s² = MLT⁻¹ and linear density m = kg/m = ML⁻¹.

So,

T^{-1}  = L^{x}[MLT^{-2} ]^{y}[ML^{-1} ]^{z}\\

collecting the like bases, we have

T^{-1} = [L^{x + y -z}][M^{y + z} ][T^{-2y} ] \\L^{0} M^{0} T^{-1} = [L^{x + y -z}][M^{y + z} ][T^{-2y} ]

Equating powers on both sides, we have

x + y - z = 0  (1)

y + z = 0       (2)

-2y = -1         (3)

From (3), y = 1/2

From (2), z = -y = -1/2

Substituting y and z into (1), we have

x + y - z = 0

x + 1/2 - (-1/2) = 0

x + 1/2 + 1/2 = 0

x + 1 = 0

x = -1

So,

f = L^{x}T^{y}m^{z}\\f = L^{-1}T^{\frac{1}{2} }m^{\frac{-1}{2} }

f = \frac{1 }{L}\sqrt{\frac{T}{m} }

8 0
3 years ago
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