Answer:
See below.
Step-by-step explanation:
The rocket's flight is controlled by its initial velocity and the acceleration due to gravity.
The equation of motion is h(t) = ut + 1.2 g t^2 where u = initial velocity, g = acceleration due to gravity ( = - 32 ft s^-2) and t = the time.
(a) h(t) = 64t - 1/2*32 t^2
h(t) = 64t - 16t^2.
(b) The graph will be a parabola which opens downwards with a maximum at the point (2, 64) and x-intercepts at (0, 0) and (4, 0).
The y-axis is the height of the rocket and the x-axis gives the time.
Maximum height = 64 feet, Time to maximum height = 2 seconds, and time in the air = 4 seconds.
No, since 0 doesn't belong to the domain.
Answer:
Let the total distance Aileen ran be 'x'
Let the distance ran by Andrew be 'y'
Refer to graph attached for graphical representation of distance travelled by both.
Applying the formula,
distance=speed*time
x=20*t Equation 1
y= 15*t equation 2
Since it can be easily understood by the graph attached, that
x=150+y equation 3
Now putting values of x and y in equation 3
20*t =150 +15*t.
5t= 150
t=30 seconds.
putting the values of t in both the equation 1 and 2
x=20t
=20*30
x = 600 feet
So the distance ran by Aileen is 600 feet, whereas Andrew ran 450 feet.
Step-by-step explanation:
Do not mind the names just change them. I had the same question before with different names so that is why. Hope this helps:)
Tan(58)=10/x
x=10/tan(58)
x= 6.2
