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Black_prince [1.1K]
3 years ago
14

Subtract: 4x/x^2-25 - 2/x^2+2x-15

Mathematics
1 answer:
Alex777 [14]3 years ago
4 0

Answer: \dfrac{4x^2-14x+10}{(x-5)(x+5)(x-3)}

Step-by-step explanation:

Given

Subtract the expression

\Rightarrow \dfrac{4x}{x^2-25}-\dfrac{2}{x^2+2x-15}\\\\\Rightarrow \dfrac{4x}{(x-5)(x+5)}-\dfrac{2}{x^2+5x-3x-15}\\\\\Rightarrow \dfrac{4x}{(x-5)(x+5)}-\dfrac{2}{(x+5)(x-3)}\\\\\text{Take the LCM and subtract}\\\\\Rightarrow \dfrac{4x(x-3)-2(x-5)}{(x-5)(x+5)(x-3)}\\\\\Rightarrow \dfrac{4x^2-12x-2x+10}{(x-5)(x+5)(x-3)}\\\\\Rightarrow \dfrac{4x^2-14x+10}{(x-5)(x+5)(x-3)}

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Step-by-step explanation:

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If g (x)=2x + 1, find g (a + h)- g (a).
Amiraneli [1.4K]
I hope this helps you

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slega [8]

Answer:

5.2

Step-by-step explanation:

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The subtraction is a little easier if you borrow a power of 10 from the 10^8, multiplying 1.1 by 10.

simply subtract 5.8 from 11.0.

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6 0
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We are interested in the dimensions of a certain square. A rectangle has a length of 5 units more than the side of the square an
JulijaS [17]
Lets consider the side of square be 'x' units
So as per data,
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and also as per data, the areas of rectangle and square are equal.
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Area of square = Side* Side= x*x = x^{2}  <- equation2

As per given data, Equation1 and equation 2 are equal
so 
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So the side of square = 5 units  

For Square, both dimensions are equal.




4 0
3 years ago
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ExtremeBDS [4]

Answer:

It is cluster

Step-by-step explanation:

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