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Black_prince [1.1K]

3 years ago

14

Subtract: 4x/x^2-25 - 2/x^2+2x-15

1 answer:

Alex777 [14]3 years ago

4 0

Answer: $\dfrac{4x^2-14x+10}{(x-5)(x+5)(x-3)}$

Step-by-step explanation:

Given

Subtract the expression

$\Rightarrow \dfrac{4x}{x^2-25}-\dfrac{2}{x^2+2x-15}\\\\\Rightarrow \dfrac{4x}{(x-5)(x+5)}-\dfrac{2}{x^2+5x-3x-15}\\\\\Rightarrow \dfrac{4x}{(x-5)(x+5)}-\dfrac{2}{(x+5)(x-3)}\\\\\text{Take the LCM and subtract}\\\\\Rightarrow \dfrac{4x(x-3)-2(x-5)}{(x-5)(x+5)(x-3)}\\\\\Rightarrow \dfrac{4x^2-12x-2x+10}{(x-5)(x+5)(x-3)}\\\\\Rightarrow \dfrac{4x^2-14x+10}{(x-5)(x+5)(x-3)}$

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2 years ago

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3 years ago

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