Step-by-step explanation:
a) substitute x values:
6-2(0) = 6
6-2(1) = 4
6-2(2) = 2
6-2(3) = 0
6-2(4) = -2
6-2(5) = -4
b) rewrite equation as y=-2x+6.
this shows a negative slope with a y-intercept of 6.
c) 3=6-2x
-6 -6
-3 = -2x
divide both sided by 2
-3/-2 = x
3/2=x
-3(x+3)= -3(x+1)-5
-3x+9=-3x+3-5
so you would have just distributed then you combine like terms and get
-3x+9=-3x-2
then add two to both sides and get
-3x+9=-3x-2
-3x+2=-3x+2
-3x+11=-3x
+3x+11=+3x
0x+11=0x
so 11+0x
divide both by zero and you get x+0
Please provide the table
Thanks,
Johnny
Answer:
Step-by-step explanation:
1) ΔCPD & ΔEPF
∠CPD = ∠EPF { Vertically opposite angles}
∠CDP = ∠PFE {CD║EF, FD is transversal, Alternate interior angles are equal}
ΔCPD ≈ΔEPF {AA criteria for similarity }
![\frac{DC}{EF} =\frac{PC}{EP}\\\\\\\frac{27}{EF}=\frac{15}{7.5}\\\\](https://tex.z-dn.net/?f=%5Cfrac%7BDC%7D%7BEF%7D%20%3D%5Cfrac%7BPC%7D%7BEP%7D%5C%5C%5C%5C%5C%5C%5Cfrac%7B27%7D%7BEF%7D%3D%5Cfrac%7B15%7D%7B7.5%7D%5C%5C%5C%5C)
Cross multiply
EF * 15 = 27 * 7.5
![EF =\frac{27*7.5}{15}\\\\](https://tex.z-dn.net/?f=EF%20%3D%5Cfrac%7B27%2A7.5%7D%7B15%7D%5C%5C%5C%5C)
EF = 27 * 0.5
EF = 13.5 cm
ii) EF // AB, so Triangles ACB & ECF are similar triangles
![\frac{AB}{EF}=\frac{AC}{EC}\\\\\frac{22.5}{13.5}=\frac{AC}{22.5}](https://tex.z-dn.net/?f=%5Cfrac%7BAB%7D%7BEF%7D%3D%5Cfrac%7BAC%7D%7BEC%7D%5C%5C%5C%5C%5Cfrac%7B22.5%7D%7B13.5%7D%3D%5Cfrac%7BAC%7D%7B22.5%7D)
![AC= \frac{22.5*22.5}{13.5}\\\\AC=37.5 cm](https://tex.z-dn.net/?f=AC%3D%20%5Cfrac%7B22.5%2A22.5%7D%7B13.5%7D%5C%5C%5C%5CAC%3D37.5%20cm)
AC = 37.5 cm
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