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Neko [114]
2 years ago
9

Divide. Write your answer as a fraction in simplest form. − 7 1/0÷2/5=

Mathematics
1 answer:
MrMuchimi2 years ago
8 0

Answer:

-71/4

Step-by-step explanation:

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There are 10 pens in a box. There are x red pens in the box. All the other pens are blue. Jack takes at random two pens from the
expeople1 [14]

The probability that one of each color is selected is \frac{10x - x^2}{45}

<h3>Probabilities</h3>

The probability of an event is the chances of the said event

The given parameters are:

  • Total  = 10
  • Red = x
  • Blue = 10 - x

<h3>Calculating the required probability</h3>

The probability that one of each color is selected is calculated as follows:

P = P(Blue) \times P(Red) + P(Red) \times P(Blue)

So, we have:

P = \frac{10 - x}{10} \times \frac{x}{9} + \frac{x}{10} \times \frac{10 - x}{9}

This gives

P = \frac{x(10 - x)}{90} +\frac{x(10 - x)}{90}

Take LCM

P = \frac{2x(10 - x)}{90}

Simplify the above expression

P = \frac{x(10 - x)}{45}

Expand

P = \frac{10x - x^2}{45}

Hence, the probability that one of each color is selected is P = \frac{10x - x^2}{45}

Read more about probabilities at:

brainly.com/question/7965468

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3 years ago
A group of cat owners was asked about the number of cats each owns. The results are shown in the frequency table. Number of Freq
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Answer:

Cats Owned B. 2 3

Hope I helped! :)

8 0
3 years ago
Eva has £6.05 in her moneybox.
PIT_PIT [208]

Answer:

11 of 20p, 22 of 10p and 33 of 5p

Step-by-step explanation:

Eva has 20p, 10p and 5p coins, total of £6.05 = 605p

Let 20p=x, 10p=y, 5p=z

<u>Then</u>:

  • 20x + 10y + 5z = 605
  • y : x = 2 : 1 ⇒ x= y/2
  • y : z = 2 : 3 ⇒ z= 3y/2

<u>Rewriting the first equation considering next two:</u>

  • 10y + 10y + 7.5y = 605
  • 27.5y = 605
  • y= 605/27.5
  • y= 22
  • x= y/2 = 22/2 = 11
  • z = 3y/2 = 3*11 = 33

<u>Answer:</u> 11 of 20p coins, 22 of 10p coins and 33 of 5p coins

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3 years ago
Which of the b-values satisfy the following inequality?5 &lt; b - 3Choose all the answers that apply: A.) b = 8B.) b = 9C.) b =
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[tex]\begin{gathered} \text{The inequality is,} \\ 5
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