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grandymaker [24]
3 years ago
5

Mark bought 8 boxes a week later half of all his boxes were destroyed in a fire there are now only 20 boxes left with how many d

id he start?
Let it b represent how many boxes he started with

Equation or inequality:

Mark began with:
Mathematics
1 answer:
anzhelika [568]3 years ago
8 0

9514 1404 393

Answer:

  • equation: 1/2(s +8) = 20
  • Mark began with 32 boxes

Step-by-step explanation:

Let s represent the number Mark started with. After buying 8 more, he then had s+8. After the fire, he had ...

  (1/2)(s +8) = 20

This equation can be solved by multiplying by 2, then subtracting 8.

  s +8 = 40

  s = 32

Mark began with 32 boxes.

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the 11th term in a geometric sequence is 48 and the common ratio is 4. the 12th term is 192 and the 10th term is what?
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<u>Given</u>:

The 11th term in a geometric sequence is 48.

The 12th term in the sequence is 192.

The common ratio is 4.

We need to determine the 10th term of the sequence.

<u>General term:</u>

The general term of the geometric sequence is given by

a_n=a(r)^{n-1}

where a is the first term and r is the common ratio.

The 11th term is given is

a_{11}=a(4)^{11-1}

48=a(4)^{10} ------- (1)

The 12th term is given by

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<u>Value of a:</u>

The value of a can be determined by solving any one of the two equations.

Hence, let us solve the equation (1) to determine the value of a.

Thus, we have;

48=a(1048576)

Dividing both sides by 1048576, we get;

\frac{3}{65536}=a

Thus, the value of a is \frac{3}{65536}

<u>Value of the 10th term:</u>

The 10th term of the sequence can be determined by substituting the values a and the common ratio r in the general term a_n=a(r)^{n-1}, we get;

a_{10}=\frac{3}{65536}(4)^{10-1}

a_{10}=\frac{3}{65536}(4)^{9}

a_{10}=\frac{3}{65536}(262144)

a_{10}=\frac{786432}{65536}

a_{10}=12

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2)  g(0)=8(\frac{1}{2} )^{0}

3)  g(0)=8*1

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