Answer:
1) The solve by graphing will the preferred choice when the equation is complex to be easily solved by the other means
Example;
y = x⁵ + 4·x⁴ + 3·x³ + 2·x² + x + 3
2) Solving by substitution is suitable where we have two or more variables in two or more (equal number) of equations
2x + 6y = 16
x + y = 6
We can substitute the value of x = 6 - y, into the first equation and solve from there
3) Solving an equation be Elimination, is suitable when there are two or more equations with coefficients of the form, 2·x + 6·y = 23 and x + y = 16
Multiplying the second equation by 2 and subtracting it from the first equation as follows
2·x + 6·y - 2×(x + y) = 23 - 2 × 16
2·x - 2·x + 6·y - 2·y = 23 - 32
0 + 4·y = -9
4) An example of a linear system that can be solved by all three methods is given as follows;
2·x + 6·y = 23
x + y = 16
Step-by-step explanation:
Answer:
35 Quarters and 36 Dimes
Step-by-step explanation:
d + q = 71
10 + 25 = 1235
10 x 36 = 360
25 x 35 = 875
360 + 875 = 1235
Answer:
y = -2/5x -1
Step-by-step explanation:
The slope intercept form is
y = mx+b where m is the slope and b is the y intercept
6x+15y = -15
Subtract 6x from each side
6x-6x +15y = -6x-15
15y = -6x-15
Divide each side by 15
15y/15 = -6x/15 -15/15
y = -2/5x -1
10-3=7
7 divided by 0.25 equals 28
Answer: 28 games