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Alexeev081 [22]
3 years ago
6

Looking for the steps to determine how 2 - 3x = -x - 8

Mathematics
1 answer:
RideAnS [48]3 years ago
3 0

Answer:

so what you do is PAY ATTENTION IN CLAS!!!!!

Step-by-step explanation:

I know this because i pay attention and ace my quizzes.

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A cylindrical stool has a base of diameter 70cm and height 25cm.find the cost of painting 50 such atools.,if the cost per m2 is
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It would be 32cm because the diameter corresponding
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Which shows all the prime factors for 24?
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All the primes of  24 is 1,2,3,4,6,8,12,and 24
5 0
3 years ago
HELP PLZZZZZ
Dmitry_Shevchenko [17]

Answer: Option (D) Add the exponents and keep the same base. Then find the reciprocal and change the sign of the exponent.

Explanation:

Given expression:

(2^3)(2^{-4})

<em>Step-1: </em>Add the exponents and keep the same base by using x^a*x^b = x^{a+b} property.

(2^3)(2^{-4}) = 2^{(3+(-4))} = 2^{-1}

Step-2: The reciprocal of 2^{-1} is \frac{1}{2^{-1}}, which is 2^1

Step-3: The exponent of 2^1 is +1; therefore, change the sign of exponent. The end expression will now become:

2^{-1}

Hence, the correct option is (D) Add the exponents and keep the same base. Then find the reciprocal and change the sign of the exponent.

3 0
3 years ago
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How many times larger is the value of the 8 in 80,351 than the value of the 8 in 95,852
NeTakaya
I believe it is 100 times larger as it is in the hundreds place for one, and the ten thousands place for the other
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7 0
3 years ago
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The amount A of the radioactive element radium in a sample decays at a rate proportional to the amount of radium present. Given
slavikrds [6]

Answer:

a) \frac{dm}{dt} = -k\cdot m, b) m(t) = m_{o}\cdot e^{-\frac{t}{\tau} }, c) m(t) = 10\cdot e^{-\frac{t}{2438.155} }, d) m(300) \approx 8.842\,g

Step-by-step explanation:

a) Let assume an initial mass m decaying at a constant rate k throughout time, the differential equation is:

\frac{dm}{dt} = -k\cdot m

b) The general solution is found after separating variables and integrating each sides:

m(t) = m_{o}\cdot e^{-\frac{t}{\tau} }

Where \tau is the time constant and k = \frac{1}{\tau}

c) The time constant is:

\tau = \frac{1690\,yr}{\ln 2}

\tau = 2438.155\,yr

The particular solution of the differential equation is:

m(t) = 10\cdot e^{-\frac{t}{2438.155} }

d) The amount of radium after 300 years is:

m(300) \approx 8.842\,g

4 0
3 years ago
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