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shutvik [7]
2 years ago
13

What is the total number of common tangents that can be drawn to the circles?

Mathematics
1 answer:
erastovalidia [21]2 years ago
6 0

Answer:

B. 0

Step-by-step explanation:

The circles do not intersect, tangents require intersection

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-4 (w+1) -24 Please help guys!
Alenkasestr [34]

Answer:

-4w -28

Step-by-step explanation:

-4 (w+1) -24

Distribute

-4w -4 -24

Combine like terms

-4w -28

4 0
3 years ago
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What is the exact value of tan (StartFraction 5 pi Over 8 EndFraction)
melisa1 [442]

9514 1404 393

Answer:

  (d)  -√((2+√2)/(2-√2))

Step-by-step explanation:

5π/8 is a 2nd-quadrant angle whose reference angle is greater than π/4. This means the tangent is negative with a magnitude greater than 1. The only reasonable choice is ...

  \displaystyle -\sqrt{\frac{2+\sqrt{2}}{2-\sqrt{2}}}

_____

<em>Additional comment</em>

This simplifies to -(1+√2). Your calculator can verify the choice for you.

4 0
2 years ago
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Find the equation of the normal to the curve y=x^2-2x^2-4x+1 at thepoint (-1,2)​
balandron [24]

Answer:

y=-\frac{1}{3}x+\frac{5}{3}

Step-by-step explanation:

Assuming that the first exponent in the formula for the curve should be 3, not 2...

y=x^3-2x^2-4x+1

The derivative is

y'=3x^2-4x+4

The slope of the tangent line at the point (-1, 2) is the value of the derivative at x = -1.

y'|_{x=-1} = 3(-1)^2-4(-1)+4=3-4+4=3

The slope of the normal line is the opposite reciprocal of the slope of the tangent line.

m_{\text{normal} = -\frac{1}{3}

Using the Point-Slope form of a linear equation, the normal line is

y-2=-\frac{1}{3}(x-(-1))\\y-2=-\frac{1}{3}(x+1)\\y=-\frac{1}{3}x-\frac{1}{3}+2\\y=-\frac{1}{3}x+\frac{5}{3}

5 0
2 years ago
Express this equation in logarithmic form.bx = n
Usimov [2.4K]
It will be written like <span>log (base b) N = x . </span>
7 0
2 years ago
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Evaluate Ic2 + b2l, given a = 5, b = -3, and c= -2.
LenKa [72]

Answer:

Ic² + b²l = 13 units.

Step-by-step explanation:

We have to evaluate the expression Ic² + b²l with unknowns b and c and having the values of b and c respectively - 3 and - 2.

Now, Ic² + b²l

= I(- 2)² + (- 3)²l {Putting the values of b and c}

= I4 + 9l  

= I13l

= 13 units.

Therefore, Ic² + b²l = 13 units. (Answer)

5 0
2 years ago
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