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lesantik [10]
3 years ago
14

The point (-3,-1) lies in the quadrant: A.​

Mathematics
1 answer:
xenn [34]3 years ago
3 0

Answer:

\displaystyle QUADRANT\:III

Step-by-step explanation:

\displaystyle [POSITIVE, NEGATIVE] → QUADRANT\:IIII \\ [NEGATIVE, NEGATIVE] → QUADRANT\:III \\ [NEGATIVE, POSITIVE] → QUADRANT\:II \\ [POSITIVE, POSITIVE] → QUADRANT\:I

I am joyous to assist you at any time.

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Solve the following system of linear equations.
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To solve a problem like this, you will need to use substitution or elimination. For the sake of an example I will solve this using substitution.

First, solve one of the equations for x or y:
3x-5y=-39
3x=-39+5y
X=(-39+5y)/3

Then substitute for the value of x in the second equation:
6x+2y=-42
6((-39+5y)/3)+2y=-42

Solve for y:
-78+10y +2y=-42
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12y=36
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Once you've solved for y, you can plug in it's value to find x:
X=-39+5(3)/3
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Answer:

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Step-by-step explanation:

We know the perimeter of a triangle is the sum of the three sides

P = s1+s2+s3

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and two of the legs are 2 x^4 + 2 x − 1  since it is an isosceles triangle

P = 2s1 + s3

Subtract 2s1 from each side

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P -2s1 =s3

Substituting what we know

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Distribute the -2

5 x^4 − 2 x^3 + x − 3 - 4 x^4 -4 x + 2 = s3

Combine like terms

5 x^4-4x^4 − 2 x^3 + x  -4 x -3+ 2 = s3

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