A = cross sectional area of the pipe. When the pressure is expressed in terms of the equivalent height of a column of that fluid, as is common with water, the friction loss is expressed as S, the "head loss" per length of pipe, a dimensionless quantity also known as the hydraulic slope.
Answer:
The approximate number of gallons of water that flow over the waterfall in 1 day is:
Step-by-step explanation:
To obtain the answer to the question, you must multiply the number gallons of water flow over a waterfall each second (6.5 x 10^5 gal/s) by the number of seconds in a day (8.6 x 10^4 s), as I show you below:
- Gallons of water that flow over the waterfall in 1 day = Number of gallons * Number of seconds in a day.
- Gallons of water that flow over the waterfall in 1 day = 6.5 x 10^5 gal/<u>s</u> * 8.6 x 10^4 <u>s</u>
Now, we must cancel the seconds, then:
- <u>Gallons of water that flow over the waterfall in 1 day = 5.59 x 10^10 gallons</u>
How you can see, <em>once you have multiplied these two values, the answer is the same to the option A</em>.
Answer:
The value of x in this equation is 8.
Step-by-step explanation:
5x - 1 = 6x - 9
Subtract 6x on both sides.
-x - 1 = -9
Add 1 to both sides.
-x = -8
Divide by -1 on both sides.
x = 8
Answer:
I believe be simplified it would be rounded so it will be 6.7
Step-by-step explanation:
Answer:
m<13
Step-by-step explanation: