Question

16 - 2r = 3r + 6r + 1 what is r?

Answer 1

$\\ \sf\longmapsto 16-2r=3r+6r+1$

$\\ \sf\longmapsto 16-2r=9r+1$

$\\ \sf\longmapsto 16-1=9r+2r$

$\\ \sf\longmapsto 11r=15$

$\\ \sf\longmapsto r=\dfrac{15}{11}$

Answer 2

Answer: r = 15/11

Step-by-step explanation:

Given

16 - 2r = 3r + 6r + 1

Combine like terms

16 - 2r = 9r + 1

Add 2r on both sides

16 - 2r + 2r = 9r + 1 + 2r

16 = 11r + 1

Subtract 1 on both sides

16 - 1 = 11r + 1 - 1

15 = 11r

Divide 11 on both sides

15 / 11 = 11r / 11

$\boxed{r=\frac{15}{11} }$

Hope this helps!! :)

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