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katrin2010 [14]
3 years ago
7

You invest $5000 into an account that has a 2.7% annual interest rate and is compounded quarterly. Approximately how long will i

t take until you have $7,500 in your account?​
Mathematics
1 answer:
allsm [11]3 years ago
4 0

Since the interest is compounded, we will have to use the compound interest formula.

We Weill plug 7500 in for A, because that's the amount of money that we want to have at the end of some amount of time.

5000 will go in for P because that's the starting amount.

2.7% will be converted into a decimal percentage form. You can do this by dividing by 100, which you will get .027, and then plug that in for r, the rate.

Since the interest is compounded quarterly, n = 4.

After a bit of number crunching, you will get to the point where you have to solve for an exponent. You can easily do this by using the natural log ln(). One property of logarithm is that you can take the exponent and place it in front of the log. Now you can divide both sides to separate and solve for t.

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8 0
3 years ago
Let T be the plane-2x-2y+z =-13. Find the shortest distance d from the point Po=(-5,-5,-3) to T, and the point Q in T that is cl
GaryK [48]

Answer:

d=10u

Q(5/3,5/3,-19/3)

Step-by-step explanation:

The shortest distance between the plane and Po is also the distance between Po and Q. To find that distance and the point Q you need the perpendicular line x to the plane that intersects Po, this line will have the direction of the normal of the plane n=(-2,-2,1), then r will have the next parametric equations:

x=-5-2\lambda\\y=-5-2\lambda\\z=-3+\lambda

To find Q, the intersection between r and the plane T, substitute the parametric equations of r in T

-2x-2y+z =-13\\-2(-5-2\lambda)-2(-5-2\lambda)+(-3+\lambda) =-13\\10+4\lambda+10+4\lambda-3+\lambda=-13\\9\lambda+17=-13\\9\lambda=-13-17\\\lambda=-30/9=-10/3

Substitute the value of \lambda in the parametric equations:

x=-5-2(-10/3)=-5+20/3=5/3\\y=-5-2(-10/3)=5/3\\z=-3+(-10/3)=-19/3\\

Those values are the coordinates of Q

Q(5/3,5/3,-19/3)

The distance from Po to the plane

d=\left| {\to} \atop {PoQ}} \right|=\sqrt{(\frac{5}{3}-(-5))^2+(\frac{5}{3}-(-5))^2+(\frac{-19}{3}-(-3))^2} \\d=\sqrt{(\frac{5}{3}+5))^2+(\frac{5}{3}+5)^2+(\frac{-19}{3}+3)^2} \\d=\sqrt{(\frac{20}{3})^2+(\frac{20}{3})^2+(\frac{-10}{3})^2}\\d=\sqrt{\frac{400}{9}+\frac{400}{9}+\frac{100}{9}}\\d=\sqrt{\frac{900}{9}}=\sqrt{100}\\d=10u

7 0
3 years ago
9. If f(x) = 5x-4 and f(2a) =156 , then what is the value of a?
solmaris [256]

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

f(x) = 5x - 4

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

f(2a) = 5(2a) - 4

f(2a) = 10a - 4

156 = 10a - 4

10a - 4 = 156

Add sides 4

10a - 4 + 4 = 156 + 4

10a = 160

Divide sides by 10

\frac{10a}{10}  =  \frac{160}{10}  \\

a = 16

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

7 0
3 years ago
The system of equations Y =-3x+2 and Y = 3x-6 is shown on the graph below.
Ira Lisetskai [31]

Answer:

A

Step-by-step explanation:

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Identify the triangle by its sides and angles:
navik [9.2K]

Answer: Right and isosceles

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2 years ago
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