Answer:
Both
and
are solutions to the system.
Step-by-step explanation:
In order to determine whether the two given points represent solutions to our system of equations, we must "plug" thos points into both equations and check that the equality remains valid.
Step 1: Plug
into 

The solution verifies the equation.
Step 2: Plug
into 

The solution verifies both equations. Therefore,
is a solution to this system.
Now we must check if the second point is also valid.
Step 3: Plug
into 

Step 4: Plug
into 

The solution verifies both equations. Therefore,
is another solution to this system.
Answer:
733.333333333333%
Step-by-step explanation:
Answer:
Big Container- $0.30
Medium: $0.33
small: $0.25
Step-by-step explanation:
you divided the number of ounces by the cost
for example- 30/9
small would be the best to by because it is the least cost per ounce
Answer:
WHat are you on?
Step-by-step explanation:
Answer:
179.3 square units
Step-by-step explanation:
The area of the figure is the sum of the areas of the parts. That is, the area is the sum of the area of the rectangle, and the area of the semicircle.
__
<h3>Semicircle</h3>
The area of a circle with radius 5 is ...
A = πr²
A = π(5²) = 25π
The area of the semicircle is half that:
semicircle area = (25π)/2 = 12.5π ≈ 39.3 . . . . square units
<h3>Rectangle</h3>
The area of a rectangle with length L and width W is ...
A = LW
The width of this rectangle is the diameter of the circle, twice the radius, or 10 units.
A = (14)(10) = 140 . . . . square units
<h3>Total area</h3>
The sum of the areas of the parts is ...
total area = semicircle area + rectangle area
total area = 39.3 + 140 = 179.3 . . . . square units