Answer:
A n B = {6}
Step-by-step explanation:
Given he sets A = (even numbers less than 10) and B = (multiples of 3 greater than 3)
A = {2, 4, 6, 8}
B = {3, 6, 9, 12, 15...}
A n B includes the numbers are are common to both sets i.e number that we can find in both A and B.
From the set given, we can see that the only number that exists in both set is 6, hence;
A n B = {6}
Try this:
1. sum of numbers is x+y=67, the difference between them is x-y=11
2. it is possible to make up and resolve the system:
The solutions of the equations of the situation can be:
z = 1 , y = 5, x = 4
z= 2 , y = 3, x = 5
z=3 , y = 1, x = 6
z = 0 , y = 7, x =3
The question can be expressed as a equation
6 x + 8 y + 10 z = 84
also, x + y + z = 10
⇒ x = 10- y - z
Putting it in first equation,
6(10 - y - z ) +8y + 10z = 84
⇒ 60 +2y + 4z = 84
⇒2(y + 2z ) = 14
⇒ y + 2z = 7
Now putting
z = 1 , we get y = 5,
z= 2 , y = 3
z=3 , y = 1
z = 0 , y = 7
So, only 4 possible solutions.
Therefore, there can only be 4 possible solutions for the equations.
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Answer:
6
Step-by-step explanation:
If x is the number of 1/8 yard long pieces, then the total length is x * 1/8. We know that the total length is 3/4 yards. Therefore:
x * 1/8 = 3/4
Divide:
x = (3/4) / (1/8)
To divide a fraction, multiply by its reciprocal:
x = (3/4) * (8/1)
x = 24/4
x = 6
She has 6 pieces.
Answer:
Ok what is the problem
Step-by-step explanation:
