Part A
The equation is b = 36*a or simply b = 36a
We take the size of the farm 'a' and multiply it by 36 to get the number of bushels of corn 'b'.
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Part B
The 36 means there are 36 times more bushels of corn compared to the size of the farm in acres
For example, if the size is 2 acres then
b = 36*a
b = 36*2
b = 72
yielding 72 bushels of corn
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Part C
Along the first row you should have: 25 and 30 in the missing blanks (over 900 and 1080 respectively)
You find this by dividing the value of b over 36
eg: b/36 = 900/36 = 25
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Then along the bottom row you should have the following for the blanks: 0, 360, 1800
These values are found by multiplying the 'a' value by 36
eg: if a = 10 then b = 36*a = 36*10 = 360
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Part D
Plot any two points you want from the table back in part C
So plot say (0,0) and (10,360). Then draw a straight line through those two points.
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Part E
The point (30,1080) means a = 30 and b = 1080
So if the farm is 30 acres, then it can produce 1080 bushels of corn
Notice how
b = 36*a
b = 36*30 <<-- replace 'a' with 30
b = 180
And how this matches up with the fourth column of the table in part C. So you can use this part to get a hint of how to fill out the table (or at least know what one column looks like)
Answer:
Step-by-step explanation:
Area of the circle = 1400π
ie. πr^2 = 1400π . ie r^2 =1400. So r=10√14
Area A = πr^2.Differentiate w.r.t.t
dA/dt = 2πr. dr/dt
900 = 2×π×10√14 .dr/dt
So. dr/dt = 900/2×π×10√14 = 45/π√14 m/sec.
Hope this answer helps you :)
Have a great day
Mark brainliest
Answer:
sorry I dont know
Step-by-step explanation:
Answer: 1102
Explain: 8 x 9 = 72
72 x 3 = 216
216 x 5 = 1080
1080 - 4 = 1076
1076 + 28 = 1104
1104 - 2 = 1102
It looks like you have the domain confused for the range! You can think of the domain as the set of all "inputs" for a function (all of the x values which are allowed). In the given function, we have no explicit restrictions on the domain, and no situations like division by 0 or taking the square root of a negative number that would otherwise put limits on it, so our domain would simply be the set of all real numbers, R. Inequality notation doesn't really use ∞, so you could just put an R to represent the set. In set notation, we'd write
and in interval notation,
The <em>range</em>, on the other hand, is the set of all possible <em>outputs</em> of a function - here, it's the set of all values f(x) can be. In the case of quadratic equations (equations with an x² term), there will always be some minimum or maximum value limiting the range. Here, we see on the graph that the maximum value for f(x) is 3. The range of the function then includes all values less than or equal to 3. As in inequality, we can say that
,
in set notation:
(this just means "f(x) is a real number less than or equal to 3")
and in interval notation:
![(-\infty,3]](https://tex.z-dn.net/?f=%20%28-%5Cinfty%2C3%5D%20)
