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3 years ago

Which decimal is equivalent to 188/11 a.17.09 b.17.009 c.17.1709 d.17.17090

Mathematics

2 answers:

horsena [70]3 years ago

8 0

Answer:

188/ 11= 17.09

Step-by-step explanation:

(a) option is correct .

omeli [17]3 years ago

6 0

Answer:

17 .09 is the decimal equivalent to 188/11 .

I HOPE YOUR DAY GOES GREAT.

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What is the value of b and c?

melomori [17]

in STR,

ST=SR

therefore, t=r(angles opposite equal sides of a triangle are equal)

T=73

C+73+73=180(ASP of triangle)

C=34

7 0

3 years ago

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Calculate the partial sum S for the sequence 243,81,27,....

Llana [10]

Answer:363

Step-by-step explanation:

We have to find partial sum for the sequence 243 , 81 , 27 ..... up to 5 terms(S5 given)

The sequence actually is 3^5,3^4.,3^3.....

Therefore first 5 terms are 1) 3^5 I.e. 243

2) 3^4 I.e. 81

3) 3^3 I.e. 27

4)) 3^2 I.e. 9

5) 3^1 I.e. 3

Adding all those no. we get partial sum of first 5 no. of the sequence

So, 243 + 81 + 27 + 9 + 3

= 363

Hope it helps!!!

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3 years ago

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Identify the coefficient in the term 7x^2 y^3 A7 B2 C 3

Fed [463]

Answer:
a. 7

Explanation:
A coefficient is the number in front of the variable that is to be multiplied by said variable. Simply identify the coefficient in the term provided to solve the problem.

8 0

3 years ago

PLEASE HELP DUE TODAY!!! GIVING BRAINLIEST TO THE PEOPLE WHO ANSWER ALL!!! I JUST WANT TO FINISH THIS AND GO TO SLEEEEP!!!!!!!

guapka [62]

Answer:

1 = 144

2 = 80

3 = 192

4 = 1209.6 or 1209

5 = 375

Step-by-step explanation:

8 0

3 years ago

The probability that an American CEO can transact business in a foreign language is .20. Twelve American CEOs are chosen at rand

NNADVOKAT [17]

Answer with Step-by-step explanation:

We are given that

The probability that an American CEO can transact business in foreign language=0.20

The probability than an American CEO can not transact business in foreign language= $1-0.20=0.80$

Total number of American CEOs chosen=12

a. The probability that none can transact business in a foreign language= $12C_0(0.20)^0(0.80)^{12}$

Using binomial theorem $nC_r(1-p)^{n-r}p^r$

The probability that none can transact business in a foreign language= $\frac{12!}{0!(12-0)!}(0.8)^{12}=(0.8)^{12}$

b.The probability that at least two can transact business in a foreign language= $1-P(x=0)-p(x=1)=1-((0.8)^{12}+12C_1(0.8)^{11}(0.2))=1-((0.8)^{12}+12(0.8)^{11}}(0.2))$

c.The probability that all 12 can transact business in a foreign language= $12C_{12}(0.8)^0(0.2)^{12}$

The probability that all 12 can transact business in a foreign language= $\frac{12!}{12!}(0.2)^{12}=(0.2)^{12}$

5 0

3 years ago