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Studentka2010 [4]
3 years ago
6

What is perfect machine ​

Physics
2 answers:
Jlenok [28]3 years ago
7 0
A perfect machine is when nothing Of the components break over time and last over long periods of use and over long periods of years used!
Fittoniya [83]3 years ago
5 0

Answer:

Explanation:

A machine is which no part of the work done on the machine is wasted, is called an ideal or perfect machine

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Explain how an intrusive igneous rock could become a metamorphic rock and then an extrusive igneous rock.
sleet_krkn [62]
1.igneous rocks are formed when magma or lava cools and hardens
2. the cooling rate of the rock
5 0
3 years ago
Help plzzzzzzz i need thissssssssss
frutty [35]

Answer:

The final graph

Explanation:

The graph that curves downwards is negative acceleration. While the position decreases the slop increases.

8 0
3 years ago
A meter stick is suspended vertically at a pivot point 22 cm from the top end. It is rotated on the pivot until it is horizontal
suter [353]

Answer:

5.82812 rad/s

Explanation:

L = Length of meter stick = 1 m = 100 cm

m_c = The center of mass of the stick = \frac{L}{2}-0.22=0.5-0.22=0.28\ m

\omega = Angular velocity

Moment of inertia of the system is given by

I=I_c+mr^2\\\Rightarrow I=\frac{mL^2}{12}+mr^2\\\Rightarrow I=\frac{m1^2}{12}+m0.28^2\\\Rightarrow I=m(\frac{1}{12}+0.0784)

As the energy in the system is conserved

mgh=I\frac{\omega^2}{2}\\\Rightarrow mgh=m(\frac{1}{12}+0.0784)\frac{\omega^2}{2}\\\Rightarrow gh=(\frac{1}{12}+0.0784)\frac{\omega^2}{2}\\\Rightarrow \omega=\sqrt{\frac{2gh}{\frac{1}{12}+0.0784}}\\\Rightarrow \omega=\sqrt{\frac{2\times 9.81\times 0.28}{\frac{1}{12}+0.0784}}\\\Rightarrow \omega=5.82812\ rad/s

The maximum angular velocity is 5.82812 rad/s

4 0
3 years ago
Why are collisions between galaxies more likely than collisions between stars within a galaxy?
KatRina [158]

Answer:

stars share a gravitational force with the galaxy while nearby galaxies do not share a gravitational field.

Explanation:

stars will not collide because they are bound by a gravitational orbit around the galaxy

8 0
3 years ago
A binary star system consists of two stars of masses m1 and m2. The stars, which gravitationally attract each other, revolve aro
zubka84 [21]

Answer:

 a₂ = m₁ / m₂ a₁

Explanation:

For this exercise we note that the attraction between the two stars is an action and reaction force, therefore it has the same magnitude, but it is applied to each of the bodies

Let's apply Newton's second law on the star 1

     F₁ = m₁ a₁

Newton's second law in star 2

       F₂ = m₂ a₂

       | F₁ | = | F₂ |

      m₁  a₁ = m₂  a₂

      a₂ = m₁ / m₂ a₁

8 0
3 years ago
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