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andrew-mc [135]
3 years ago
14

How much force does it take to bring a 1,050 N car from rest to a velocity of 42 m/s in 13 seconds?

Physics
1 answer:
frozen [14]3 years ago
5 0

Answer:

F = 339.23 N

Explanation:

Weight of a car, W = 1050 N

Initial velocity, u = 0

Final velocity, v = 42 m/s

Time, t = 13 s

The weight of an object is given by :

W = mg

g is the acceleration due to gravity

m=\dfrac{W}{g}\\\\m=\dfrac{1050}{10}\\\\m=105\ kg

The force acting on car is :

F=ma\\\\F=\dfrac{m(v-u)}{t}\\\\F=\dfrac{105\times (42-0)}{13}\\\\F=339.23\ N

So, the force acting on the car is 339.23 N.

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Andru [333]
It would be B

Explanation:
Because if you're not measuring in inches you want to go the next one down other than inches which would be millimeters!(: hope this helps.
6 0
3 years ago
Read 2 more answers
Two cars collide at an intersection. One car has a mass of 1600 kg and is
pickupchik [31]

The combined momentum is 4000 kg m/s south

Explanation:

The total combined momentum of the two cars is given by the vector addition of the momenta of the two cars.

For this problem, we choose north as positive direction and south as negative direction.

The momentum of the first car travelling north is given by:

p_1 = m_1 v_1

where

m_1 = 1600 kg is the mass of the car

v_1 = +8 m/s is its velocity

Substituting,

p_1 = (1600)(8)=+12800 kg m/s

The momentum of the second car travelling south is given by:

p_2 = m_2 v_2

where

m_2 = 1400 kg is the mass of the car

v_2= -12 m/s is its velocity (negative because the car travels south)

Substituting,

p_2 = (1400)(-12)=-16800 kg m/s

And therefore, the combined momentum is

p=p_1 + p_2 = +12800 + (-16800)=-4000 kg m/s

where the negative sign means the direction of the total momentum is south.

Learn more about momentum:

brainly.com/question/7973509

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4 0
3 years ago
If an object accelerates from rest, with a constant of 8 m/s2, what will its velocity be after 35s?
AlladinOne [14]

Answer:

<em>Its speed will be 280 m/s</em>

Explanation:

<u>Constant Acceleration Motion</u>

It's a type of motion in which the speed of an object changes by an equal amount in every equal period of time.

If a is the constant acceleration, vo the initial speed, vf the final speed, and t the time, vf can be calculated as:

v_f=v_o+at

The object accelerates from rest (vo=0) at a constant acceleration of a=8\ m/s^2. The final speed at t=35 seconds is:

v_f=0+8*35

v_f=280\ m/s

Its speed will be 280 m/s

5 0
3 years ago
A 48-volt source is required to furnish 192 watts to a parallel circuit consisting of three resistors of equal value. What is th
dem82 [27]

Answer:

36 Ω

Explanation:

Since the 3 resistors are connected in parallel.

The combined resistance of the resistor is

1/Rc = 1/R + 1/R + 1/R ...................... Equation 1

Where Rc = combined resistance of the three resistor, R1 = Resistance of each of the resistor

Rc = R/3 ....................... Equation 2

The formula of power is given as

P = V²/Rc

Rc = V²/P ................ Equation 3

Where V = Voltage, R =  Combined Resistance, P = power.

Given: V = 48 V, 192 W.

Substitute into equation 3

Rc = 48²/192

Rc = 12 Ω

From equation 2

Rc = R/3

R = 3Rc

Where Rc = 12 Ω

R = 3×12

R = 36 Ω

Hence the resistance on each resistor = 36 Ω

4 0
3 years ago
If two point sources of light are being imaged by this telescope, what is the maximum wavelength λ at which the two can be resol
Alex

This question is incomplete.Here is complete one

Consider a telescope with a small circular aperture of diameter 2.0 centimeters. If two point sources of light are being imaged by this telescope, what is the maximum wavelength (lambda) at which the two can be resolved if their angular separation is 3.0x10^-5 radians? Express your answer in nanometers

Answer:

λ =492nm

Explanation:

Given Data

diameter=2.0 cm

angular separation=3.0x10^-5 radians

λ=?

Solution

sin(theta) = 1.22 x λ /D

λ=(0.02×sin(3.0×10⁻⁵))/1.22

λ=492nm

6 0
4 years ago
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