Question

How much force does it take to bring a 1,050 N car from rest to a velocity of 42 m/s in 13 seconds?

Answer 1

Answer:

F = 339.23 N

Explanation:

Weight of a car, W = 1050 N

Initial velocity, u = 0

Final velocity, v = 42 m/s

Time, t = 13 s

The weight of an object is given by :

W = mg

g is the acceleration due to gravity

$m=\dfrac{W}{g}\\\\m=\dfrac{1050}{10}\\\\m=105\ kg$

The force acting on car is :

$F=ma\\\\F=\dfrac{m(v-u)}{t}\\\\F=\dfrac{105\times (42-0)}{13}\\\\F=339.23\ N$

So, the force acting on the car is 339.23 N.