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swat32
3 years ago
15

Find the magnitude of vector A = i - 2j + 3k O V14 10 O4

Physics
1 answer:
koban [17]3 years ago
7 0

Answer:

The magnitude of the given vector is \sqrt{14}

Explanation:

For any given vector \overrightarrow{r}=x\widehat{i}+y\widehat{j}+z\widehat{k}

The magnitude is given by

|r|=\sqrt{x^2+y^2+z^2}

comparing with the given vector \overrightarrow{A}=1\widehat{i}-2\widehat{j}+3\widehat{k}

we get

x = 1, y = -2, z = 3

Thus the magnitude of vector A is

|r|=\sqrt{1^2+(-2)^2+3^2}\\\\\therefore |r|=\sqrt{14}

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