V₁ = 900.0 mL
T₁ = 27.0ºC + 273 = 300 K
V₂ = ?
T₂ = 132.0 + 273 = 405 K
V₁ / T₁ = V₂ / T₂
900.0 / 300 = V₂ / 405
300 x V₂ = 405 x 900.0
300 x V₂ = 364500
V₂ = 364500 / 300
V₂ = 1215 mL
hope this helps!
Number of moles = 2.00
Volume = 4.00 L
M = n / V
M = 2.00 / 4.00
M = 0.5 mol/L
hope this helps!
Answer:
can you please be more clear on your question
Answer:
1.41 moles H2O2(with sig figs)
Explanation:
okay so what is the molar mass of H2O2= (1.008 g/mol)2+(16.00g/mol)2= (2.016+ 32.00) g/ mol
= 34. 02 g/mol
48.0g H2O2* 1 mol H2O2/ 34.02 g H2O2= 1.41 mol H2O2