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Anit [1.1K]
4 years ago
9

A gas with a volume of 300 mL at 150 °C is heated until its volume is 600 mL. What is the new temperature of the gas if the pres

sure is unaltered?

Chemistry
1 answer:
Mandarinka [93]4 years ago
3 0

.012K

Use the equation of \frac{V1}{T1} = \frac{V2}{T2}.

Replace V with volume and T with the temperature. However, with the temperature, make sure to convert the celsius into kelvin by adding 273.

Hope this helps!

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A galvanic cell is set up with two cells containing a cadmium electrode in 0. 250 m cd(no3)2 solution and an iron electrode in 0
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The cell potential is 0.01934 V at 25°C.

<h3>What is a galvanic cell?</h3>

A galvanic cell, also known as a voltaic cell, is an electrochemical cell that converts the chemical energy generated by spontaneous redox reactions into electrical energy.

The main components of a galvanic cell are

Anode – Oxidation occurs at the anode

Cathode – Reduction occurs at the cathode

Salt bridge – consists of electrolytes that are needed to complete the circuit in a galvanic cell.

Half-cells – It is important as reduction and oxidation reactions are separated into compartments.

External circuit – it helps in Conducting the flow of electrons between electrodes

At cathode,

Cd^{2+}(aq) + 2e^-\rightarrow Cd(s)

At anode,

Fe(s)+2e^-\rightarrow Fe^{2+}(aq)

Overall cell reaction

Fe(s)+Cd^{2+}(aq)\rightarrow Fe^{2+}(aq) + Cd(s)

E^o_{cell} = E^o_{cathode} - E^o_{anode}

          = -0.40 -(0.44) = 0.04 V

Nernst equation is given by

E_{cell} = E^o_{cell} - \frac{2.303RT}{nF} logQ

At 25°C

E_{cell} = E^o_{cell} - \frac{0.0592V}{n} logQ

Here, n = 2 and log Q = log \frac{0.250}{0.050} = 0.699

E_{cell}  = 0.01934 V

The cell potential is 0.01934 V at 25°C

Learn more about galvanic cell:

brainly.com/question/13918634

#SPJ4

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Ideal Gas Law Formula.

Brainliest?

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