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Anit [1.1K]
3 years ago
9

A gas with a volume of 300 mL at 150 °C is heated until its volume is 600 mL. What is the new temperature of the gas if the pres

sure is unaltered?

Chemistry
1 answer:
Mandarinka [93]3 years ago
3 0

.012K

Use the equation of \frac{V1}{T1} = \frac{V2}{T2}.

Replace V with volume and T with the temperature. However, with the temperature, make sure to convert the celsius into kelvin by adding 273.

Hope this helps!

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starting with the idea of isostasy and ending with plate tectonics, explain how scientists understanding of the earth's crust ha
anzhelika [568]

Answer:

Isostasy controls the regional elevations of continents and ocean floors in accordance with the densities of their underlying rocks. ... The concept of isostasy played an important role in the development of the theory of plate tectonics.

8 0
3 years ago
2C2H2(g) + 502(g) → 4C02(g) + 2H20(g) reaction type?
ratelena [41]

Answer:

The answer is combustion.

7 0
2 years ago
25<br> #of<br> protons<br> # of<br> neutrons<br> # of<br> electrons
Molodets [167]

Answer:

16

Explanation:

number of electrons should also be 16.

5 0
3 years ago
iron is made by a reduction of iron oxide with carbon monoxide. Fe2O3+3CO-2Fe+3CO2. Calculate the mass of iron that can be forme
lyudmila [28]

Answer:

Mass = 88.12 g

Explanation:

Given data:

Mass of iron oxide = 126 g

Mass of iron formed = ?

Solution:

Chemical equation:

Fe₂O₃ + 3CO    →      2Fe + 3CO₂

Number of moles of iron oxide:

Number of moles = mass/molar mass

Number of moles = 126 g/ 159.69 g/mol

Number of moles = 0.789 mol

Now we will compare the moles of iron with iron oxide.

                      Fe₂O₃           :             Fe

                         1                 :               2

                   0.789              :            2/1×0.789 = 1.578 mol

Mass of iron:

Mass = number of moles ×molar mass

Mass = 1.578 mol × 55.84 g/mol

Mass = 88.12 g

4 0
2 years ago
The rate of effusion of an unknown gas was measured and found to be 11.9 mL/min. Under identical conditions, the rate of effusio
iren2701 [21]

Answer : The correct option is, (B) CO_2

Solution :

According to the Graham's law, the rate of effusion of gas is inversely proportional to the square root of the molar mass of gas.

R\propto \sqrt{\frac{1}{M}}

or,

(\frac{R_1}{R_2})=\sqrt{\frac{M_2}{M_1}}       ..........(1)

where,

R_1 = rate of effusion of unknown gas = 11.9\text{ mL }min^{-1}

R_2 = rate of effusion of oxygen gas = 14.0\text{ mL }min^{-1}

M_1 = molar mass of unknown gas  = ?

M_2 = molar mass of oxygen gas = 32 g/mole

Now put all the given values in the above formula 1, we get:

(\frac{11.9\text{ mL }min^{-1}}{14.0\text{ mL }min^{-1}})=\sqrt{\frac{32g/mole}{M_1}}

M_1=44.2g/mole

The unknown gas could be carbon dioxide (CO_2) that has approximately 44 g/mole of molar mass.

Thus, the unknown gas could be carbon dioxide (CO_2)

5 0
3 years ago
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