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Sliva [168]
3 years ago
7

-HELP-How many molecules are contained in 125 grams of oxygen gas (O2)?

Chemistry
1 answer:
strojnjashka [21]3 years ago
3 0

Answer:

62.50

Explanation:

I divided the 125 in the result is 62.50 but it is considered a 62.

never mine:)

You might be interested in
What volume of oxygen (in L) is produced
sveticcg [70]

Answer:

12.36 L.

Explanation:

We'll begin by calculating the number of mole in 147.1 g of lead(II) nitrate, Pb(NO₃)₂. This can be obtained as follow:

Molar mass of Pb(NO₃)₂ = 207.2 + 2[14.01 + (16×3)]

= 207.2 + 2[14.01 + 48]

= 207.2 + 2[62.01]

= 207.2 + 124.02

= 331.22 g/mol

Mass of Pb(NO₃)₂ = 147.1 g

Mole of Pb(NO₃)₂ =?

Mole = mass / Molar mass

Mole of Pb(NO₃)₂ = 147.1 / 331.22

Mole of Pb(NO₃)₂ = 1.104 moles.

Next, we shall determine the number of mole of oxygen gas, O₂, produce from the reaction. This can be obtained as follow:

2Pb(NO₃)₂ —> 2PbO + 4NO₂ + O₂

From the balanced equation above,

2 moles of Pb(NO₃)₂ decomposed to produce 1 mole of O₂.

Therefore, 1.104 moles of Pb(NO₃)₂ will decompose to produce = (1.104 × 1)/2 = 0.552 mole of O₂.

Finally, we shall determine the volume occupied by 0.552 mole of oxygen gas, O₂. This can be obtained as follow:

1 mole of O₂ occupied 22.4 L at STP.

Therefore, 0.552 mole of O₂ will occupy = 0.552 × 22.4 = 12.36 L at STP.

Thus, the volume of oxygen gas, O₂ produced is 12.36 L.

6 0
2 years ago
Which statement correctly describes extreme weather?
sveta [45]

Answer: A

Explanation:

Extreme weather events follow normal climate patterns.

5 0
2 years ago
Zachary adds 9.7 g to 1.114 g.<br> How many significant figures should his answer have?
makvit [3.9K]
Always use least amount of sig figs possible. So this 9.7 would be (answer): 2 sig figs
5 0
2 years ago
After creating a prototype, which of the following would not be an appropriate next step in the design process of a new technolo
Ivanshal [37]
I would say D but i am not entirely sure 
4 0
3 years ago
How many kilograms of oseltamivir would be needed to treat all the people in a city with a population of 400000 people if each p
madam [21]

Answer:

300 kg

Explanation:

The number of people in the city, p = 400,000

The number of capsules of oseltamivir each person consumes per day, n = 2 capsules

The number of days each person consumes the oseltamivir capsules, t = 5 days

The mass of oseltamivir in each capsule, m = 75 mg

The mass of oseltamivir needed to treat all the people in the city, <em>M</em>, is given as follows;

M = n·t·m·p

∴ M (in milligrams) = (2 × 5 × 75 × 400,000) mg = 300,000,000 mg

1,000,000 mg = 1 kg

∴ 300,000,000 mg = 300 kg

The mass of oseltamivir needed to treat all the people in the city, <em>M</em> = 300 kg

3 0
3 years ago
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