F₂ + 2 NaI → 2 NaF + I₂
<span>It is given that F₂ is light yellow / colorless in hydrocarbon solvent. The student combines Fluorine water with NaI in water. Then student adds pentane in the mixture of F₂ and NaI. After dissolution, solution was observed and a colorless pentane layer was seen. Alkanes are unreactive in nature. The C-H bond in alkane is difficult to break. whereas, F₂ is very reactive and reacts vigorously with alkanes in presence of light by free radical mechanism.It is given that the color of the solution is nearly colorless. F₂ when present in hydrocarbon solvent is light yellow/ colorless/ nearly colorless. Hence, F₂ is not reacting with hydrocarbon and there is no reaction taking place (No F</span>₂ is present<span>)</span>
Answer:
Chemistry plays an important and useful role towards the development and growth of a number of industries. This includes industries like glass, cement, paper, textile, leather, dye etc. We also see huge applications of chemistry in industries like paints, pigments, petroleum, sugar, plastics, Pharmaceuticals.
Making an atom or a virus structure
Noble gases have complete valence electron shells
The compound 
will have a triple bond.
Explanation:
A compound which consists of carbon and hydrogen atoms is known as a hydrocarbon.
Alkanes, alkenes and alkynes are all hydrocarbons.
- General chemical formula of an alkane is
. In an alkane molecule, all the atoms will be bonded through single bonds.
For example, 
is propane.
- General chemical formula of an alkene is
. An alkene molecule will have atleast one double bond between two carbon atoms.
For example, 
is ethene.
- General chemical formula of an alkyne is
. An alkyne will have atleast one triple bond between two carbon atoms.
For example, is propyne.
Thus, we can conclude that out of the given options will have a triple bond.
