The first question's answer is the second choice. The second question's answer is the first choice. The third question's answer is the second choice.
Formatting is kind of messed up. I'm assuming the differential equations is dy/dx = 6x
You need to get all the x's on one side and y'all on the other.
dy =6x dx
Integrate both sides.
y = 3x^2 + C
Now plug in the given values
y(0) = 4 = 3(0)^2 + C
C = 0
y = 3x^2
Plug 1 in for x to find the value of y(1)
y(1) = 3(1)^2 = 3
Answer:
Statements 2 and 3.
Step-by-step explanation:
The first statement is impossible since you cannot have half a person. The last statement is also incorrect, because it would imply that the total number of students in the class is -29. The second statement is correct, if you assume that x and y represent either the number of male or female students. The third statement is possible, and the numbers add up to 29. Finally, the fourth statement is impossible because it would imply that the class had negative male students. Hope this helps!
Answer:
Simplifying
logx + -4 = 0
Reorder the terms:
-4 + glox = 0
Solving
-4 + glox = 0
Solving for variable 'g'.
Move all terms containing g to the left, all other terms to the right.
Add '4' to each side of the equation.
-4 + 4 + glox = 0 + 4
Combine like terms: -4 + 4 = 0
0 + glox = 0 + 4
glox = 0 + 4
Combine like terms: 0 + 4 = 4
glox = 4
Divide each side by 'lox'.
g = 4l-1o-1x-1
Simplifying
g = 4l-1o-1x-1
2 6/7 ÷ 2/3
= 20/7 ÷ 2/3
20/7 × 3/2
= 60/14
reduce to it's lowest term
30/7 = 4 2/7
