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viktelen [127]
2 years ago
9

HELP PLEASE!

Mathematics
2 answers:
saul85 [17]2 years ago
7 0
Area=5rad5 times 2rad5 equals 50 Bc rad 5 times rad 5 is rad 25 or 5 and 2 timers 5 is ten so now it is 5 times 10=50
wel2 years ago
3 0

Answers:

\text{Perimeter} = 14\sqrt{5}\\\\\text{Area} = 50\\\\

=======================================================

Work Shown:

L = 2\sqrt{5} = \text{length}

W = 5\sqrt{5} = \text{width}

P = perimeter

P = 2*(L+W)\\\\P = 2*(2\sqrt{5}+5\sqrt{5})\\\\P = 2*(7\sqrt{5})\\\\P = 14\sqrt{5}\\\\

-------------

A = area

A = L*W\\\\A = (2\sqrt{5})*(5\sqrt{5})\\\\A = (2*5)(\sqrt{5}*\sqrt{5})\\\\A = 10\sqrt{5*5}\\\\A = 10\sqrt{25}\\\\A = 10*5\\\\A = 50\\\\

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Can someone solve this?
Gemiola [76]

Answer:

B : 4x\sqrt{17}

Step-by-step explanation:

If you divide a rhombus using its diagonals, you get 4 right triangles, whose legs are both 1/2 the length of the diagonals.

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3 years ago
Suppose that the proportions of blood phenotypes in a particular population are as follows: A B AB O 0.48 0.13 0.03 0.36 Assumin
Serggg [28]

Answer:

P(O and O) =0.1296

P=0.3778

Step-by-step explanation:

Given that

blood phenotypes in a particular population

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B=0.13

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O=0.36

As we know that when A and B both are independent that

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The probability that both phenotypes O are in independent:

P(O and O)= P(O) X P(O)

P(O and O)= 0.36 X 0.36 =0.1296

P(O and O) =0.1296

The probability that the phenotypes of two randomly selected individuals match:

Here  four case are possible

So

P=P(A and A)+P(B and B)+P(AB and AB)+P(O and O)

P=0.48 x 0.48 + 0.13 x 0.13 + 0.03 x 0.03 + 0.36 x 0.36

P=0.3778

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3 years ago
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