For this problem, you would have to use a system of equations. Hope this helps!
I ain't gonna explain how I got to this cuz I'm quite tired rn but trust me the answer is 2c²
If in the triangle ABC , BF is an angle bisector and ∠ABF=41° then angle m∠BCE=8°.
Given that m∠ABF=41° and BF is an angle bisector.
We are required to find the angle m∠BCE if BF is an angle bisector.
Angle bisector basically divides an angle into two parts.
If BF is an angle bisector then ∠ABF=∠FBC by assuming that the angle is divided into two parts.
In this way ∠ABC=2*∠ABF
∠ABC=2*41
=82°
In ΔECB we got that ∠CEB=90° and ∠ABC=82° and we have to find ∠BCE.
∠BCE+∠CEB+EBC=180 (Sum of all the angles in a triangle is 180°)
∠BCE+90+82=180
∠BCE=180-172
∠BCE=8°
Hence if BF is an angle bisector then angle m∠BCE=8°.
Learn more about angles at brainly.com/question/25716982
#SPJ1
Answer:
-8.57142857143
Step-by-step explanation:
-8.57142857143
Answer:
21.5 mm^2
Step-by-step explanation:
First find the area of the square
A = s^2 = 10^2 =100
Then find the area of the circle
d = 10 so r = d/2 = 10/2 =5
A = pi r^2
A = 3.14 (5)^2 =78.5
The difference is the shaded region
100-78.5 =21.5