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3 years ago

25 mi/h ≈ _______ft/s

Mathematics

2 answers:

Stella [2.4K]3 years ago

7 0

1 mile is 5280 feet.

1 hours is 3 600 seconds

So 25 mi/h is 25* 5280 = 132 000 feets in 3 600 seconds.

So : 132 000 /3 600 = 1 320 / 36 =36.66

25 mi/h≈ 36.6666 ft/s

mihalych1998 [28]3 years ago

4 0

There are 5280 feet to 1 mile, and 3600 seconds to 1 hour. So

(25 mi/h) × (5280 ft/mi) × (1/3600 h/s) = 110/3 ft/s ≈ 36.7 ft/s

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Factor the polynomial and use the zeros to identify its graph. x4 − 5x3 − 20x2 + 60x + 144

Monica [59]

The zeros of the polynomial are -3, -2, 4 and 6 and the graph of the polynomial is graph (a)

<h3>How to factor the polynomial?</h3>

The polynomial is given as:

P(x) = x^4 - 5x^3 - 20x^2 + 60x + 144

Expand the polynomial function

P(x) = x^4 - 10x^3 + 5x^3 + 24x^2 - 50x^2 + 6x^2 + 120x - 60x + 144

Rewrite the function as:

P(x) = x^4 - 10x^3 + 24x^2 + 5x^3 - 50x^2 + 120x + 6x^2 - 60x + 144

Factorize the function

P(x) = x^2(x^2 - 10x + 24) + 5x(x^2 - 10x + 24) + 6(x^2 - 10x + 24)

Factor out x^2 - 10x + 24

P(x) = (x^2 + 5x + 6)(x^2 - 10x + 24)

Expand each bracket

P(x) = (x^2 + 3x + 2x + 6)(x^2 - 4x - 6x + 24)

Factorize each bracket

P(x) = [x(x + 3) + 2(x + 3)][x(x - 6) - 4(x - 6)]

Factor out x + 3 and x - 6

P(x) = (x + 3)(x + 2)(x - 4)(x - 6)

Set to 0

(x + 3)(x + 2)(x - 4)(x - 6) = 0

Solve for x

x =-3, -2, 4 and 6

Hence, the zeros of the polynomial are -3, -2, 4 and 6 and the graph of the polynomial is graph (a)

Read more about polynomials at:

brainly.com/question/20896994

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see attached

Step-by-step explanation:

You can do these yourself fairly easily. Copy the figure and the coordinate axes onto a piece of tracing paper (tissue paper or even facial tissue will work, too), then rotate the copied figure 90° clockwise.

Line up the origin of the axes and make sure the axes you drew line up with the ones on the original figure. For 90° clockwise rotation, what was the +y axis will now align with the +x axis. Copy the rotated figure from the tracing paper back to the graph on your problem page in its new location. (You can cut out the figure, if necessary. Just be sure to make note of the position relative to the axes.)

This sort of physical activity reinforces the thinking you need to do to mentally rotate the figures. It is worth the effort.