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igomit [66]
3 years ago
5

Problem Solve for t. 2(t+1) = 10

Mathematics
1 answer:
Svetllana [295]3 years ago
5 0

t=4

explanation

2(t+1)=10

2t+2=10

2t=8

t=4

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dimulka [17.4K]
\frac{100}{3*5}
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Can someone help me solve x
evablogger [386]

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there a 158 beats per minute in a certain taylor swift song. if the song is 3 minutes and 30 seconds long, how many total beats
sergiy2304 [10]
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4 0
3 years ago
Write a definite integral that represents the area of the region. (Do not evaluate the integral.) y1 = x2 + 2x + 3 y2 = 2x + 12F
Svet_ta [14]

Answer:

A = \int\limits^3__-3}{9}-{x^{2}} \, dx = 36

Step-by-step explanation:

The equations are:

y = x^{2} + 2x + 3

y = 2x + 12

The two graphs intersect when:

x^{2} + 2x + 3 = 2x + 12

x^{2} = 0

x_{1}  = 3\\x_{2}  = -3

To find the area under the curve for the first equation:

A_{1} = \int\limits^3__-3}{x^{2} + 2x + 3} \, dx

To find the area under the curve for the second equation:

A_{2} = \int\limits^3__-3}{2x + 12} \, dx

To find the total area:

A = A_{2} -A_{1} = \int\limits^3__-3}{2x + 12} \, dx -\int\limits^3__-3}{x^{2} + 2x + 3} \, dx

Simplifying the equation:

A = \int\limits^3__-3}{2x + 12}-({x^{2} + 2x + 3}) \, dx = \int\limits^3__-3}{9}-{x^{2}} \, dx

Note: The reason the area is equal to the area two minus area one is that the line, area 2, is above the region of interest (see image).  

3 0
3 years ago
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inna [77]

Answer: \frac{16}{3}

Step-by-step explanation:

For this exercise it is important to remember  the multiplication of signs:

(+)(+)=+\\(-)(-)=+\\(-)(+)=-\\(+)(-)=-

In this case, given the following expression:

(-8)(-\frac{2}{3})

You can idenfity that both factors are negative. Then, the product (The result of the multiplication) will be positive.

Then, in order to get the product, you need to multiply the numerator of the fraction by -8. So, you get:

 \frac{(-2)(-8)}{3}=\frac{16}{3}

You can notice that the numerator and the denominator of the fraction obtained cannot be divided by the same number; therefore, the fraction cannot be simplified.

3 0
3 years ago
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