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Genrish500 [490]
3 years ago
13

If l=5 and b=3 find the value of 2 (l+b)​

Mathematics
2 answers:
Gre4nikov [31]3 years ago
8 0

Answer:

16

Step-by-step explanation:

2 (l+b)​

Let l=5 and b=3

2 (5+3)​

Parentheses first

2(8)

Multiply

16

fiasKO [112]3 years ago
5 0

Answer:

16

Step-by-step explanation:

Plug in:

2 (l + b)

2 (5 + 3)

2 (8)

 16

Hope this helped.

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Step 1: -3(+ 2) = 5(x - 7)
madam [21]

Answer:

The answer is Steps 1 and 2.                                Step 1: -3(x+2) = 5(x-7)

                                                                               Step 2: -3x-6 = 5x-35

Step-by-step explanation:

4 0
3 years ago
An investor has an account with stock from two different companies. Last year, her stock in Company A was worth $2690 and her st
Mrac [35]

Answer:

<h2> 14.7 %</h2>

Step-by-step explanation:

let us total the amount in her portfolio

Company A was worth $2690

Company B was worth $2980.

Total = $5670

when The stock in Company A decreases by 20%  she will have

$2690 *0.8=  $2152

Company A will worth $2152

when The stock in Company B decreases by 10%  she will have

$2980 *0.9=  $2682

Company A will worth  $2682

In all after the decline in are portfolio is $2152+$2682= $4834

the difference for the original amount in her investment is = $5670-$4834

= $836

The total percentage decrease in the investor's stock account

= (836/5670)*100= 0.147*100= 14.7 %

3 0
3 years ago
What is the first step in solving this system by elimination?
kherson [118]

You want to try and get rid of one of the variables ( x or y) so you would multiply the second equation by 2 which would make the x variable -2x which then when added to the first equation would eliminate the x variable.

Answer: c. Multiply the second equation by 2.

4 0
3 years ago
Please help and please show work<br>will give brainlyist
Komok [63]

If I am understanding this right, since the <em>c </em>is a variable, you'd have to solve the equation and have the variable in the and result.

the sqrt525^7 = 3359983566.19

So you'd have to simplify this and add the <em>c</em> to the end of it. Unless your work is fractions.

(I take Algebra II I should be more confident on this topic, this is just what makes the most sense)

7 0
3 years ago
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Stolb23 [73]
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