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anastassius [24]
3 years ago
10

A state requires that all boat licenses consist of the letter A or M followed by any five digits. What is the number of groups o

f letters and numbers available for boat licenses?
Mathematics
1 answer:
torisob [31]3 years ago
7 0

Answer:

200000

Step-by-step explanation:

The boat licenses are strings of six elements. Let's count the number of ways of constructing such string with the given conditions.

There are 2 ways of choosing the first character of the string (A or M). The second character can be any digit, so there are 10 possible choices. The third character is also any digit, so it can be chosen in 10 ways. Similarly, the fourth character can be chosen in 10 ways, and the fifth character can be chosen in 10 ways.

By the product rule there are 2×10×10×10×10×10=2×10^5=200000 ways to choose all the characters. Every choice of characters becomes a unique string (boat license) thus the number of avaliable boat licenses is 200000.s

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The amounts of nicotine in a certain brand of cigarette are normally distributed with a mean of 0.917 g and a standard deviation
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Answer:

z = \frac{0.872-0.917}{\frac{0.303}{\sqrt{37}}}= -0.903

And we can find this probability to find the answer:

P(z

And using the normal standar table or excel we got:

P(z

Step-by-step explanation:

Let X the random variable that represent the amounts of nocatine of a population, and for this case we know the distribution for X is given by:

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We have the following info from a sample of n =37:

\bar X= 0.872 the sample mean

And we want to find the following probability:

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z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}

And if we find the z score for the value of 0.872 we got:

z = \frac{0.872-0.917}{\frac{0.303}{\sqrt{37}}}= -0.903

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P(z

And using the normal standar table or excel we got:

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3 years ago
Mean for 16, 12, 13, 22
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Answer:

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Mr. Akika has 49 21 cent and 31 cent stamps all told. The stamps are worth $13.39. how many of each kind of stamps does he have?
Lana71 [14]

Mr Akika has 18  21-cent stamp and 31 31-cent stamp.  

He has 49 21-cent and 31-cent stamps all told.

let

x = number of 21 cent stamp

y = number of 31 cent stamp

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21x + 31y = 1339

21x + 21y = 1029

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y = 310 / 10

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Therefore,

x = 49 - 31

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Therefore, Mr Akika has 18  21-cent stamp and 31 31-cent stamp.  

learn more on system of equation: brainly.com/question/1369852?referrer=searchResults

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2 years ago
Find 118% of 19 could really use some help late bloomer 
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Hello, 

<span>to find the percent of a number what we have to do is to multiply the number by de percent that we want to know and divide by 100, so:
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