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3 years ago

2x^-8x+12 -------------- 2x^-36

1 answer:

8 0

$\frac{x { }^{2} - 2x - 6x + 12}{ (x - 6)(x + 6)} \\ \\ \frac{x(x - 2) - 6(x - 2)}{(x - 6)(x + 6)} \\ \\ \frac{(x - 2)(x - 6)}{(x - 6)(x + 6)} \\ \\ \frac{x - 2}{x + 6}$

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3 years ago

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How do I factor 5n^2 +19n+12

trapecia [35]

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3 years ago

I need help with #8

NikAS [45]

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3 years ago

9/11 - 1/2 in it's simplest form

Murrr4er [49]

Answer:

7/22

Step-by-step explanation:

Step 1: Define/explain.

To subtract fractions with different denominators, you must first find the least common denominator (LCM).

You can do this by listing the multiples of each denominator.

Step 2: Solve.

11: 11, 22, 33, 44, 55, 66, 77, 88, 99, 110

2: 2, 4, 6, 8, 10, 12, 14, 16, 18, 20, 22

22 is the LCM.

Now, we change the fractions to where they both have denominators of 22.

**REMEMBER: WHICHEVER NUMBER YOU MULTIPLY THE DENOMINATOR BY, YOU MULTIPLY IT BY THE NUMERATOR AS WELL!!**

$9/11*2/2=18/22$

$1/2*11/11=11/22$

Now, subtract as normal.

$18/22-11/22=7/22$

$7/22 (simplified).$

Step 3: Conclude.

Therefore, 9/11 - 1/2 = 7/22.

5 0

3 years ago

(1) Factor the GCF out of the trinomial on the left side of the equation. (2 points: 1 for the GCF, 1 for the trinomial) 2x²+6x-

Tanya [424]

Step-by-step explanation:

(1) Factor the GCF out of the trinomial on the left side of the equation. (2 points: 1 for the GCF, 1 for the trinomial) 2x²+6x-20=0

2x²+6x-20

2(x²+3x-10)

the factors are 2 and (x²+3x-10)

(2) Factor the polynomial completely. (4 points: 2 point for each factor)

2(x²+3x-10)

2(x²-2x+5x-10)

2(x(x-2) + 5(x-2)) group like terms

2(x+5)(x-2)

(3) If a product is equal to zero, we know at least one of the factors must be zero. And the constant factor cannot be zero. So set each binomial factor equal to 0 and solve for x, the width of your project. (2 points: 1 point for each factor)

constant = 2 cannot be zero

the other factors are (x+5) and (x-2)

(x+5)=0 => x= -5

(x-2)=0 => x=2

(4) What are the dimensions of your project? Remember that the width of your project is represented by x. (2 points: 1 point for each dimension)

thank you so much, sorry if it's a little confusing!!

(it is indeed confusing, because physical dimensions cannot be negative)

The dimensions of the project (assumed a rectangle) are +2 and -5

3 0

3 years ago